Solve c =(a² + 3b)/4 for b.Bruv take all my points I literally blow at math :'(
1 answer:
Answer:

Step-by-step explanation:
First: multiply both sides by 4. 4 times c is 4c and the other sides cancels out as you are doing the inverse operation of division
Then, you have 
Subtract both sides by a squared
DO NOT TAKE THE SQUARE ROOT! This is because it is a squared plus 3b so you have to do the inverse of addition
From that you get 
Finally, divide both sides by 3.
You get 
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Answer:
Let
S= #small candles
L= #Large candles
S+ L =>20
3.50S + 5.00L < 80
Step-by-step explanation:
First, complete the square.
y = (x^2 - 4x + 4) + 2
y = (x - 2)^2 + 2
There you go. Have a nice day! :)
[tex] 3(x + 5) - 2(x + 2) = 20 \\
3x + 15 - 2x - 4 = 20\\
5x + 11 = 20\\
5x = 9\\
x = 1\frac{4}{5} [tex]
Answer:
x=9, y=10. (9, 10). The two numbers are 9 and 10.
Step-by-step explanation:
3x+5y=77
x+y=19
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3x+5y=77
-3(x+y)=-3(19)
---------------------
3x+5y=77
-3x-3y=-57
-------------------
2y=20
y=20/2
y=10
x+10=19
x=19-10
x=9
Step-by-step explanation:
Sorry I cant get any more answers but I really hope that this helps