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3 years ago

Solve c =(a² + 3b)/4 for b.Bruv take all my points I literally blow at math :'(

Mathematics

1 answer:

Sati [7]3 years ago

4 0

Answer:

$b=\frac{4c-a^{2} }{3}$

Step-by-step explanation:

First: multiply both sides by 4. 4 times c is 4c and the other sides cancels out as you are doing the inverse operation of division

Then, you have $4c=a^{2} +3b$

Subtract both sides by a squared

DO NOT TAKE THE SQUARE ROOT! This is because it is a squared plus 3b so you have to do the inverse of addition

From that you get $4c-a^{2} =3b$

Finally, divide both sides by 3.

You get $b=\frac{4c-a^{2} }{3}$

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Solving these gives us

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Therefore the only solution is $m=-4$ .

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3 years ago

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1 year ago

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3 years ago

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Solve c =(a² + 3b)/4 for b.Bruv take all my points I literally blow at math :'(​

Solve c =(a² + 3b)/4 for b.Bruv take all my points I literally blow at math :'(