Seconds because one second is less than one minute
A coin has one of two outcomes: heads or tails.
Each has an equal probability of occurring, meaning that they each have a 50% chance to occur. (They need to add up to 100% because they include all the outcomes, divide that into two equal parts and...)
This is what we call theoretical probability. It's a guess as to how probability <em>should</em> work. Like in the experiment, it's not always going to be 50-50.
What <em>actually happens</em> is called experimental probability. This may vary slightly from theoretical probability because you can't predict probability with complete certainty, you can only say what is <em>most likely to happen</em>.
We want to find the probability of getting heads in our experiment so we can compare it to the theoretical outcome. To do this, we need to compare the number of heads to the total number of outcomes.
We have 63 heads, and a total of 150 coin flips.
That makes the probability of getting a heads 63/150.
The hard part is getting this ratio into a percent.
You can try simply dividing, but you should be able to notice something here.
SInce the top and the bottom of our fraction are both divisible by 3, we can <em>simiplify</em>.
63 ÷ 3 = 21
150 ÷ 3 = 50
So we could say that 63/150 = 21/50.
A percent is basically a fraction out of 100.
Just like you can divide the parts of a ratio by the same number and it will stay the same, you can also multiply. To get the fraction out of 100, let's multiply by 2.
(since 50 × 2 = 100)
21 × 2 = 42
50 × 2 = 100
21/50 = 42/100 = 42%
Comparing our experimental probability to the theoretical one...it is 8% lower.
<h3>
Answer: 80 degrees</h3>
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Explanation:
I'm assuming that segments AD and CD are tangents to the circle.
We'll need to add a point E at the center of the circle. Inscribed angle ABC subtends the minor arc AC, and this minor arc has the central angle AEC.
By the inscribed angle theorem, inscribed angle ABC = 50 doubles to 2*50 = 100 which is the measure of arc AC and also central angle AEC.
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Focus on quadrilateral DAEC. In other words, ignore point B and any segments connected to this point.
Since AD and CD are tangents, this makes the radii EA and EC to be perpendicular to the tangent segments. So angles A and C are 90 degrees each for quadrilateral DAEC.
We just found angle AEC = 100 at the conclusion of the last section. So this is angle E of quadrilateral DAEC.
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Here's what we have so far for quadrilateral DAEC
- angle A = 90
- angle E = 100
- angle C = 90
- angle D = unknown
Now we'll use the idea that all four angles of any quadrilateral always add to 360 degrees
A+E+C+D = 360
90+100+90+D = 360
D+280 = 360
D = 360-280
D = 80
Or a shortcut you can take is to realize that angles E and D are supplementary
E+D = 180
100+D = 180
D = 180-100
D = 80
This only works if AD and CD are tangents.
Side note: you can use the hypotenuse leg (HL) theorem to prove that triangle EAD is congruent to triangle ECD; consequently it means that AD = CD.
You would evaluate by plugging in the given number of 7 to get your answer.
2.20 rounded to the nearest tenth is 2.2 it is already rounded if it was 2.29 it would be 2.3