$\bf (\stackrel{x_1}{6}~,~\stackrel{y_1}{5})\qquad (\stackrel{x_2}{9}~,~\stackrel{y_2}{15}) ~\hfill \stackrel{slope}{m}\implies \cfrac{\stackrel{rise} {\stackrel{y_2}{15}-\stackrel{y1}{5}}}{\underset{run} {\underset{x_2}{9}-\underset{x_1}{6}}}\implies \cfrac{10}{3}$

7 0

3 years ago

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In triangle ABC, c = 9 m/_B = 65° and a = 105. Find b.

tresset_1 [31]

Answer:

b = 101.52

Step-by-step explanation:

b^2 = a^2 + c^2 - 2ac CosB

b^2 = 105^2 + 9^2 - 2(105)(9) Cos 65°

b^2 = 11 106 - 798.75

b^2 = 10 307.25

b = 101.52

5 0

3 years ago

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circle centered at the origin has a radius of 5 units. The terminal side of an angle, θ, intercepts the circle in Quadrant IV at

astraxan [27]

Answer:

Step-by-step explanation:

x²+y² = 5²

3²+y² = 25

y² = 16

y = ±√16 = ±4

Since the terminal side is in quadrant IV, y = -4

sinθ = -4/5

5 0

3 years ago

Need help with the slope​

Need help with the slope