The point G on AB such that the ratio of AG to GB is 3:2 is; G(4.2, 2)
How to partition a Line segment?
The formula to partition a line segment in the ratio a:b is;
(x, y) = [(bx1 + ax2)/(a + b)], [(by1 + ay2)/(a + b)]
We want to find point G on AB such that the ratio of AG to GB is 3:2.
From the graph, the coordinates of the points A and B are;
A(3, 5) and B(5, 0)
Thus, coordinates of point G that divides the line AB in the ratio of 3:2 is;
G(x, y) = [(2 * 3 + 3 * 5)/(2 + 3)], [(2 * 5 + 3 * 0)/(2 + 3)]
G(x, y) = (21/5, 10/5)
G(x, y) = (4.2, 2)
Read more about Line segment partition at; brainly.com/question/17374569
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Answer:
3
Step-by-step explanation:
Answer:
x ≥ -6
Step-by-step explanation:
-3x-7 ≤ 11
-3x-7+7 ≤ 11+7
-3x ≤ 18
(-3x)(1) ≤ 18(-1)
3x ≤ -183x/3 ≤ -18/3
They are each multiplied by a factor of 3.5
You can calculate this by taking the length of the similar prism and divide it with the first prism 14.7/4.2 = 3.5
Do this with the width and height to be sure
20.3/5.8 = 3.5
33.6/9.6 = 3.5
Answer:
572.5
Step-by-step explanation:
A=6ah + 3√(3) a²= 6·8·5+3√(3)·8²≈572.55376
a is base length and h is height
