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agasfer [191]
2 years ago
12

$51.57 this is right

Mathematics
2 answers:
kkurt [141]2 years ago
8 0

Is there missing parts to this question?

notka56 [123]2 years ago
7 0

Answer: what do you mean

Step-by-step explanation:

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2. The table below shows that the distance d varies directly as the time t. Find the constant of variation and the equation whic
Artemon [7]
<h2><u>Problem Solving</u>:-</h2>

2. The table below shows that the distance d varies directly as the time t. Find the constant of variation and the equation which describes the relation.

<h2><u>Solution</u>:-</h2>

Since the distance d varies directly as the time t, then d = kt.

Using one of the pairs of values, (2, 20), from the table, substitute the values of d and t in d = kt and solve for k.

\sf{\rightarrow{d =  kt}}

\sf\rightarrow{20  = 2k }

\sf\rightarrow{K= \frac{20}{2} }

\sf\rightarrow{K={\color{magenta}{10}}}

<h2><u>Answer</u>:-</h2>
  • Therefore, the constant of variation is 10.
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3 years ago
Transformations reflection practice
SOVA2 [1]

Answer:

The Reflection:

<em>'T</em>(-2,-2), <em>'C</em>(-2,-5), <em>'Z</em>(-5,-4), <em>'F</em>(-5,0)

5 0
2 years ago
What is the area of this figure? <br><br> Enter your answer in the box
Anvisha [2.4K]
Area of box : 18*18, which is 324

area of larger triangle : 18*16/2 which is 144

area of larger triangle : 8*16/2 which is 64

add them all to get 532
7 0
3 years ago
Which of the following expressions represents the solution to x – 3 &gt; -4?
Bess [88]

Step-by-step explanation:

x - 3 > -4

= x > -4+3

= x > -1 _ Answer

8 0
3 years ago
A 1.5-mm layer of paint is applied to one side of the following surface. Find the approximate volume of paint needed. Assume tha
Mariulka [41]

Answer:

V = 63π / 200  m^3

Step-by-step explanation:

Given:

- The function y = f(x) is revolved around the x-axis over the interval [1,6] to form a spherical surface:

                                 y = √(42*x - x^2)

- The surface is coated with paint with uniform layer thickness t = 1.5 mm

Find:

The volume of paint needed

Solution:

- Let f be a non-negative function with a continuous first derivative on the interval [1,6]. The Area of surface generated when y = f(x) is revolved around x-axis over the interval [1,6] is:

                           S = 2*\pi \int\limits^a_b { [f(x)*\sqrt{1 + f'(x)^2} }] \, dx

- The derivative of the function f'(x) is as follows:

                            f'(x) = \frac{21-x}{\sqrt{42x-x^2} }

- The square of derivative of f(x) is:

                            f'(x)^2 = \frac{(21-x)^2}{42x-x^2 }

- Now use the surface area formula:

                           S = 2*\pi \int\limits^6_1 { [\sqrt{42x-x^2} *\sqrt{1 + \frac{(21-x)^2}{42x-x^2 } }] \, dx\\\\S = 2*\pi \int\limits^6_1 { [\sqrt{42x-x^2+(21-x)^2} }] \, dx\\\\S = 2*\pi \int\limits^6_1 { [\sqrt{42x-x^2+441-42x+x^2} }] \, dx\\\\S = 2*\pi \int\limits^6_1 { [\sqrt{441} }] \, dx\\S = 2*\pi \int\limits^6_1 { 21} \, dx\\\\S = 42*\pi \int\limits^6_1 { dx} \,\\\\S = 42*\pi [ 6 - 1 ]\\\\S = 42*5*\pi \\\\S = 210\pi

- The Volume of the pain coating is:

                           V = S*t

                           V = 210*π*3/2000

                          V = 63π / 200 m^3

8 0
3 years ago
Read 2 more answers
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