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AnnyKZ [126]
3 years ago
13

Consider this quadratic equation:

Mathematics
1 answer:
zhenek [66]3 years ago
6 0

Answer:

a=2

b=0

c=12

Step-by-step explanation:

The standard form of a quadratic equation is ax²+bx+c=0

Here's the given equation:

2x²+12=0

You might notice that the term bx is not there (there is just ax² and c). That means that b is 0.

The term 2x² is the term ax² in this equation. The coefficient in the term is 2, so that means that a is 2

12 has no variable, so that means it'll be c in the equation.

Hope this helps!

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A coach is assessing the correlation between the number of hours spent practicing and the average number of points scored in a g
cricket20 [7]

Answer:

a) r=\frac{9(396)-(18)(153)}{\sqrt{[9(51) -(18)^2][9(3141) -(153)^2]}}=1  

We have a perfect linear relationship between the two variables

b) m=\frac{90}{15}=6  

Nowe we can find the means for x and y like this:  

\bar x= \frac{\sum x_i}{n}=\frac{18}{9}=2  

\bar y= \frac{\sum y_i}{n}=\frac{153}{9}=17  

And we can find the intercept using this:  

b=\bar y -m \bar x=17-(6*2)=5  

So the line would be given by:  

y=6 x +5  

c) For this case the slope indicates that for each increase of the number of hours in 1 unit we have an expected increase in the score about 6 units.

And the intercept 5 represent the minimum score expected for any game

Step-by-step explanation:

We have the following data:

Number of hours spent practicing (x) 0 0.5 1 1.5 2 2.5 3 3.5 4

Score in the game (y) 5 8 11 14 17 20 23 26 29

Part a

The correlation coefficient is given:

r=\frac{n(\sum xy)-(\sum x)(\sum y)}{\sqrt{[n\sum x^2 -(\sum x)^2][n\sum y^2 -(\sum y)^2]}}  

For our case we have this:

n=9 \sum x = 18, \sum y = 153, \sum xy = 396, \sum x^2 =51, \sum y^2 =3141  

r=\frac{9(396)-(18)(153)}{\sqrt{[9(51) -(18)^2][9(3141) -(153)^2]}}=1  

We have a perfect linear relationship between the two variables

Part b

m=\frac{S_{xy}}{S_{xx}}  

Where:  

S_{xy}=\sum_{i=1}^n x_i y_i -\frac{(\sum_{i=1}^n x_i)(\sum_{i=1}^n y_i)}{n}  

S_{xx}=\sum_{i=1}^n x^2_i -\frac{(\sum_{i=1}^n x_i)^2}{n}  

With these we can find the sums:  

S_{xx}=\sum_{i=1}^n x^2_i -\frac{(\sum_{i=1}^n x_i)^2}{n}=51-\frac{18^2}{9}=15  

S_{xy}=\sum_{i=1}^n x_i y_i -\frac{(\sum_{i=1}^n x_i)(\sum_{i=1}^n y_i){n}}=396-\frac{18*153}{9}=90  

And the slope would be:  

m=\frac{90}{15}=6  

Nowe we can find the means for x and y like this:  

\bar x= \frac{\sum x_i}{n}=\frac{18}{9}=2  

\bar y= \frac{\sum y_i}{n}=\frac{153}{9}=17  

And we can find the intercept using this:  

b=\bar y -m \bar x=17-(6*2)=5  

So the line would be given by:  

y=6 x +5  

Part c

For this case the slope indicates that for each increase of the number of hours in 1 unit we have an expected increase in the score about 6 units.

And the intercept 5 represent the minimum score expected for any game

5 0
3 years ago
Juan wishes to build a garden at the bottom of his property. He wants to split it in two, like the diagram below, so he can plan
SCORPION-xisa [38]

Answer:

20 ft by 60 ft

Step-by-step explanation:

"What should the dimensions of the garden be to maximize this area?"

If y is the length of the garden, parallel to the stream, and x is the width of the garden, then the amount of fencing is:

120 = 3x + y

And the area is:

A = xy

Use substitution:

A = x (120 − 3x)

A = -3x² + 120x

This is a downward facing parabola.  The maximum is at the vertex, which we can find using x = -b/(2a).

x = -120 / (2 · -3)

x = 20

When x = 20, y = 60.  So the garden should be 20 ft by 60 ft.

4 0
3 years ago
Sorry for the bad picture quality, lol trust me I’m not android user... bUt I really am struggling! Help!-
Klio2033 [76]

Answer:

a to u

Step-by-step explanation:

3 0
3 years ago
Fourteen thousand seven hundred ninety three in standard form
NeTakaya

Answer:

14,793

Step-by-step explanation:

7 0
3 years ago
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Solve for x.<br> 0.2x – 3.2<br> = 1.8<br> 1<br> 5<br> X = ?
Hitman42 [59]

Answer:

X = 25

Step-by-step explanation:

Isolate the variable by dividing each side by factors that don't contain the variable

5 0
2 years ago
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