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Olin [163]
2 years ago
11

Solve: 5x-3+2x = 5x+3 show your work

Mathematics
2 answers:
NARA [144]2 years ago
6 0

Answer:

x = 3

Step-by-step explanation:

5x - 3 + 2x = 5x + 3. that is

7x - 3 = 5x + 3 ( subtract 5x from both sides )

2x - 3 = 3 ( add 3 to both sides )

2x = 6 ( divide both sides by 2 )

x = 3

AURORKA [14]2 years ago
5 0

Answer:

x = 3

Step-by-step explanation:

5x - 3 + 2x = 5x + 3

<em>subtract 5x from both sides</em>

5x - 5x - 3 + 2x = 5x - 5x + 3

-3 + 2x = 3

<em>add 3 to both sides</em>

-3 + 3 + 2x = 3 + 3

2x = 6

<em>divide both sides by 2</em>

2x/2 = 6/2

x = 6/2

x = 3

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3 years ago
Let n1equals50​, Upper X 1equals30​, n2equals50​, and Upper X 2equals10. Complete parts​ (a) and​ (b) below. a. At the 0.05 leve
Viefleur [7K]

Answer:

Null hypothesis:p_{1} = p_{2}  

Alternative hypothesis:p_{1} \neq p_{2}  

z=\frac{0.6-0.2}{\sqrt{0.4(1-0.4)(\frac{1}{50}+\frac{1}{50})}}=4.082    

p_v =2*P(Z>4.082)=4.46x10^{-5}  

So the p value is a very low value and using any significance level for example \alpha=0.05 always p_v so we can conclude that we have enough evidence to reject the null hypothesis, and we can say the the proportion 1 is significantly different from proportion 2.

Step-by-step explanation:

1) Data given and notation  

X_{1}=30 represent the number of people with a characteristic in 1

X_{2}=10 represent the number of people with a characteristic in 2

n_{1}=50 sample of 1 selected  

n_{2}=50 sample of 2 selected  

p_{1}=\frac{30}{50}=0.6 represent the proportion of people with a characteristic in 1

p_{2}=\frac{10}{50}=0.2 represent the proportion of people with a characteristic in 2

z would represent the statistic (variable of interest)  

p_v represent the value for the test (variable of interest)  

2) Concepts and formulas to use  

We need to conduct a hypothesis in order to check if the proportion 1 is different from proportion 2 , the system of hypothesis would be:  

Null hypothesis:p_{1} = p_{2}  

Alternative hypothesis:p_{1} \neq p_{2}  

We need to apply a z test to compare proportions, and the statistic is given by:  

z=\frac{p_{1}-p_{2}}{\sqrt{\hat p (1-\hat p)(\frac{1}{n_{1}}+\frac{1}{n_{2}})}}   (1)  

Where \hat p=\frac{X_{1}+X_{2}}{n_{1}+n_{2}}=\frac{30+10}{50+50}=0.4  

3) Calculate the statistic  

Replacing in formula (1) the values obtained we got this:  

z=\frac{0.6-0.2}{\sqrt{0.4(1-0.4)(\frac{1}{50}+\frac{1}{50})}}=4.082    

4) Statistical decision

For this case we don't have a significance level provided \alpha, but we can calculate the p value for this test.    

Since is a two sided test the p value would be:  

p_v =2*P(Z>4.082)=4.46x10^{-5}  

So the p value is a very low value and using any significance level for example \alpha=0.05 always p_v so we can conclude that we have enough evidence to reject the null hypothesis, and we can say the the proportion 1 is significantly different from proportion 2.  

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Biologists are keeping track of the different kinds of fish in Lake Michigan. Identify the type of data.
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Answer:

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Step-by-step explanation:

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Answer:

b

Step-by-step explanation:

each always has a x

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