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2 years ago

Enter the value of x that makes the equation true. 6/x = 12/3

Mathematics

1 answer:

Svetllana [295]2 years ago

5 0

hi hi hi hi hi hi hi hi hi hi hi hi

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Does this have infinite solutions or no solutions?

Papessa [141]

Answer:

when they cross u should get a perfect solution of (2,6)

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2 years ago

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Read the true statement below and tell whether the converse, inverse, and contrapositive are also true.

IgorC [24]

Converse: False because he can live somewhere else but still belong in Hawaii

Inverse: False because he can live somewhere else but still belong in Hawaii

Contrapositive: True because Honolulu belongs to Hawaii so if he doesn't live in Hawaii he absolutely can't live in Honolulu

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2 years ago

(I can mark the first correct person brainliest!)

Mashutka [201]

35 which is slope which in turn represents the speed.

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2 years ago

Komok [63]

Answer:

Future amount (A) = $1,258.77 (Approx)

Step-by-step explanation:

Given:

Amount deposit (p) = $693

Rate of interest monthly (r) = 4.9% / 12 = 0.003833

Number of month (n) = 13 × 12 = 156

Find:

Future amount (A)

Computation:

$A = p [1+r]^n \\\\ A = 693 [1+0.003833]^{156}\\\\ A= 693[1.8163]\\\\ A = 1258.77$

Future amount (A) = $1,258.77 (Approx)

6 0

2 years ago

Sviatoslav solved the quadratic equation x^2-x-1=0 by completing the square. In the process, he came up with the equivalent equa

zimovet [89]

Answer:

$x=\frac{1+\sqrt5}{2}$ and $x=\frac{1-\sqrt5}{2}$

and b= $\frac{5}{4}$

Step-by-step explanation:

We are given that a quadratic equation

$x^2-x-1=0$

We have to solve the equation by completing square and find the value of b.

$(x)^2-2\times x\times \frac{1}{2}+(\frac{1}{2})^2-(\frac{1}{2})^2-1=0$

$(x-\frac{1}{2})^2-\frac{1}{4}-1=0$

$(x-\frac{1}{2})^2-\frac{1-4}{4}=0$

$(x-\frac{1}{2})-\frac{5}{4}=0$

$(x-\frac{1}{2})^2-(\frac{\sqrt5}{2})^2=0$

$(x-\frac{1}{2})^2=(\frac{\sqrt5}{2})^2$

$x-\frac{1}{2}=\frac{\sqrt5}{2}$ and $x-\frac{1}{2}=-\frac{\sqrt5}{2}$

$x=\frac{\sqrt5}{2}+\frac{1}{2}=\frac{1+\sqrt5}{2}$

And $x=\frac{1}{2}-\frac{\sqrt5}{2}=\frac{1-\sqrt5}{2}$

Therefore, $x=\frac{1+\sqrt5}{2}$ and $x=\frac{1-\sqrt5}{2}$

and b= $\frac{5}{4}$

6 0

2 years ago