Ask question

Ask question

All categories

3 years ago

10

Must m in the equation y=mx+b always be a positive number

2 answers:

Sindrei [870]3 years ago

7 0

Not at all.

'm' turns out to be the slope of the graph of the equation.

If the graph of the equation slopes upward as it goes
from left to right, then 'm' is positive.

If the graph of the equation slopes downward as it goes
from left to right, then 'm' is negative.

Nookie1986 [14]3 years ago

4 0

'm' is the slope.

The answer is no. There could be a negative number, which means that the slope would be decreasing, or as known as a negative slope (negative rate of change). <span />

You might be interested in

Find the variables.<br> (2x)"<br> 54<br> x=

aev [14]

Answer: x= 108

Step-by-step explanation: (2x)" 54 x= 108x^2= (2^X3^3x^2 )= 108

7 0

3 years ago

Find 6889 + 3088 + 9062.

Varvara68 [4.7K]

1903

pls mark brainliest

if u want

6 0

2 years ago

Read 2 more answers

What was Fibonacci vision for the world? What did Fibonacci hope the world would be like?

ziro4ka [17]

Fibonacci saw that every thing could be created with shapes, and that he hoped the world be brighter

3 0

3 years ago

HELP ME PLEASE! 20 POINTS!!!

Grace [21]

Answer:

is in the shape of a sphere

diameter = 60 feet

radius = r = 60/2 = 30 feet

Step-by-step explanation:

volume of sphere = 4/3 × π × r³

= 4/3 × π × 30³

=4/3π × 27,000

= 36000π cubic feet

7 0

2 years ago

Read 2 more answers

Sam invests $6000 in two different accounts. The first account paid 12 %, the second account paid 7 % in interest. At the end of

Lunna [17]

Answer:

The amount in the account at 12% interest is $3400 and the amount in the second account at 7% interest is $2600

Step-by-step explanation:

Let x be the amount in the account at 12% interest

So, 6000-x is the amount in the second account at 7% interest

$SI = \frac{P \times T \times R}{100}$

First account: $SI=\frac{x \times 1 \times 12}{100}$

Second account : $SI =\frac{(6000-x) \times 1 \times 7}{100}$

We are given that At the end of the first year he had earned $590 in interest.

So, $\frac{x \times 1 \times 12}{100}+\frac{(6000-x) \times 1 \times 7}{100}=590\\x=3400$

So,the amount in the account at 12% interest is $3400

The amount in the second account at 7% interest =6000-x=6000-3400=2600

Hence the amount in the account at 12% interest is $3400 and the amount in the second account at 7% interest is $2600

8 0

3 years ago