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3 years ago

Pls answer asap! 15(12-y)+9y=150

Mathematics

2 answers:

podryga [215]3 years ago

6 0

Answer:

Y = 5

Step-by-step explanation:

noname [10]3 years ago

6 0

Answer:

y=5

Step-by-step explanation:

15(12-y)+9y=150 do the () first

180-15y+9y=150 combine the y terms

180-6y=150 subtract 180 from both sides

-6y= -30 divide by -6

y=5

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Point x is located at (-2,-6) and point z is located at (0,5). Find the y value for the point y that is located 1/5 the disteanc

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Answer:

-3 1/2

Step-by-step explanation:

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This will be: 5 - -6 = 11 units

1/5 of 11 = 1/5 × 11

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Now add 2.5 to -6

2 1/2 + -6 = -3 1/2

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3 years ago

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Step-by-step explanation:

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3 years ago

Cos^2x+cos^2(120°+x)+cos^2(120°-x)<br>i need this asap. pls help me

o-na [289]

Answer:

$\frac{3}{2}$

Step-by-step explanation:

Using the addition formulae for cosine

cos(x ± y) = cosxcosy ∓ sinxsiny

---------------------------------------------------------------

cos(120 + x) = cos120cosx - sin120sinx

= - cos60cosx - sin60sinx

= - $\frac{1}{2}$ cosx - $\frac{\sqrt{3} }{2}$ sinx

squaring to obtain cos² (120 + x)

= $\frac{1}{4}$ cos²x + $\frac{\sqrt{3} }{2}$ sinxcosx + $\frac{3}{4}$ sin²x

--------------------------------------------------------------------

cos(120 - x) = cos120cosx + sin120sinx

= -cos60cosx + sin60sinx

= - $\frac{1}{2}$ cosx + $\frac{\sqrt{3} }{2}$ sinx

squaring to obtain cos²(120 - x)

= $\frac{1}{4}$ cos²x - $\frac{\sqrt{3} }{2}$ sinxcosx + $\frac{3}{4}$ sin²x

--------------------------------------------------------------------------

Putting it all together

cos²x + $\frac{1}{4}$ cos²x + $\frac{\sqrt{3} }{2}$ sinxcosx + $\frac{3}{4}$ sin²x + $\frac{1}{4}$ cos²x - $\frac{\sqrt{3} }{2}$ sinxcosx + $\frac{3}{4}$ sin²x

= cos²x + $\frac{1}{2}$ cos²x + $\frac{3}{2}$ sin²x

= $\frac{3}{2}$ cos²x + $\frac{3}{2}$ sin²x

= $\frac{3}{2}$ (cos²x + sin²x) = $\frac{3}{2}$

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3 years ago