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Airida [17]
2 years ago
11

When Ryan was born, he weighed 7 pounds.At 6 months, he weighed 11.2 pounds. Amanda weighed 6 pounds when she was born, and 12.9

pounds at 6 months. Which baby had a greater percent increase in weight? Explain.
Mathematics
2 answers:
konstantin123 [22]2 years ago
6 0

Answer:

Amanda.

Step-by-step explanation:

Ryan was 7 pound and gained 4.2 pounds which is only around a 60% Increase. Amanda on the other hand gained 6.9 pounds which is around a 110% Increase.

Zielflug [23.3K]2 years ago
3 0

Answer:

Amanda had greater percent increase by weight.

Step-by-step explanation:

When Ryan was born, he weighed 7 pounds. At 6 months, he weighed 11.2 pounds. Amanda weighed 6 pounds when she was born, and 12.9 pounds at 6 months. Which baby had a greater percent increase in weight? Explain.

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This model represents which expression?
Romashka-Z-Leto [24]
The answer is 3 divided by 1/2
8 0
3 years ago
4> Solve by using Laplace transform: y'+5y'+4y=0; y(0)=3 y'(o)=o
harina [27]

Answer:

y=3e^{-4t}

Step-by-step explanation:

y''+5y'+4y=0

Applying the Laplace transform:

\mathcal{L}[y'']+5\mathcal{L}[y']+4\mathcal{L}[y']=0

With the formulas:

\mathcal{L}[y'']=s^2\mathcal{L}[y]-y(0)s-y'(0)

\mathcal{L}[y']=s\mathcal{L}[y]-y(0)

\mathcal{L}[x]=L

s^2L-3s+5sL-3+4L=0

Solving for L

L(s^2+5s+4)=3s+3

L=\frac{3s+3}{s^2+5s+4}

L=\frac{3(s+1)}{(s+1)(s+4)}

L=\frac3{s+4}

Apply the inverse Laplace transform with this formula:

\mathcal{L}^{-1}[\frac1{s-a}]=e^{at}

y=3\mathcal{L}^{-1}[\frac1{s+4}]=3e^{-4t}

7 0
3 years ago
A(n) _____ is any side of a polygon that shares a side with only one angle of a pair of angles.
erastovalidia [21]

Answer:

non-included

Step-by-step explanation:

A non included side of a polygon shares a side with only one angle of a pair of angles.

4 0
3 years ago
Read 2 more answers
What percent of 12 is 48<br> A. 0.25%<br> B. 4% <br> C. 25%<br> D. 40% <br> E. 400%
Step2247 [10]

Answer: the answer is 25 percent

Step-by-step explanation: 25 percent times 48 is 12

5 0
3 years ago
Define the value of the expression 3^2 x 3^{-5}
Tanya [424]

Answer:

Between 0 and 1

Step-by-step explanation:

The given expresion is

{3}^{2} \times  {3}^{ - 5}

Recall that:

{a}^{m}  \times  {a}^{n}  =  {a}^{m + n}

We apply this property of exponents to get;

{3}^{2}  \times  {3}^{ - 5}  =  {3}^{2 +  - 5}  =  {3}^{ - 3}

We rewrite to obtain a positive index as:

{3}^{2}  \times  {3}^{ - 5}  =  \frac{1}{ {3}^{3} }  =  \frac{1}{27}

Therefore the value of the expression is between 0 and 1.

8 0
3 years ago
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