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lianna [129]
2 years ago
9

Which property of multiplication is shown? r · s = s · r

Mathematics
1 answer:
kodGreya [7K]2 years ago
8 0

Answer:

That is the commutative property.

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HELP order to find the percentage of households in a town that own more than one vehicle, a survey asks 1000 randomly selected d
alekssr [168]
Answer is D jjkkkkmmm
5 0
3 years ago
Send help please!! i want to complete it asap
Nadusha1986 [10]
It’s a little complicated but here’s how it works:
Imagine a table with the intervals
0:4 , 4:6 , 6:7 , 7:10 , 10:13 (10 year intervals)
Then we have different rows
Class width: 4 , 2 , 1 , 3 , 3
Freq density: 0.2 , 0.5 , 1.2 , 0.7 , 0.3
So now calculate frequency where freq = class width * density
Freq: 0.8 , 1 , 3.6 , 2.1 , 0.9
So to find median find cumulative frequency
(Add all freq)
Cfreq = 8.4 now divide by 2 = 4.2
So find the interval where 4.2 lies.
0.8 + 1 = 1.8 + 3.6 = 5.6

So 4.2 (median) will lie in that interval 60-70 years.
7 0
2 years ago
One canned orange juice is 25% orange juice another is 5% orange juice. How many liters of each should be mixed together in orde
Cerrena [4.2K]

Answer:

X = \frac{1.6 - 0.05Y}{0.25}= 6.4 -0.2 Y  (3)

Replcaing equation (3) into equation (2) we got:

0.75(6.4 -0.2 Y) +0.95 Y = 18.4

And solving for Y we got:

4.8 -0.15 Y +0.95 Y = 18.4

0.8 Y = 13.6

Y = 17

And solving for X from equation (3) we got:

X= 6.4 -0.2*17 = 3

So we need 3L of orange juice with 25% of concentration and 17 L of orange juice with 5% of concentration

Step-by-step explanation:

For this problem we can work with the concentration of water and orange juice.

Let X the amount for the orange juice with 25% content and Y the amount for the orange juice with 5% of content

Using the concentration of orange juice we have:

0.25 X + 0.05 Y = 20*0.08  (1)

And for the water we have:

0.75 X + 0.95Y = 20*0.92  (2)

If we solve for X from equation (1) we got:

X = \frac{1.6 - 0.05Y}{0.25}= 6.4 -0.2 Y  (3)

Replcaing equation (3) into equation (2) we got:

0.75(6.4 -0.2 Y) +0.95 Y = 18.4

And solving for Y we got:

4.8 -0.15 Y +0.95 Y = 18.4

0.8 Y = 13.6

Y = 17

And solving for X from equation (3) we got:

X= 6.4 -0.2*17 = 3

So we need 3L of orange juice with 25% of concentration and 17 L of orange juice with 5% of concentration

7 0
3 years ago
What is the average (arithmetic mean) of the first 90 measurements in a certain list of 92 measurements? (1) the average of the
marishachu [46]
The sum of all the measurements is just the average times the number.

\bar x = \frac{1}{n} \sum_{i=1}^n x_i

\sum_{i=1}^n x_i = n \bar x

So if the average of all 92 is 7 the sum of those is 92 \times 7

The average of the last two is 7.2 so their sum is 2 \times 7.2

That means the sum of the first 90 is 92 \times 7 - 2 \times 7.2

so the average of the first 90 is

 \dfrac{92 \times 7 - 2 \times 7.2}{90} = 6.99556 cm



7 0
3 years ago
Write an exponential function in the form y=ab^xy=ab x that goes through points (0, 20)(0,20) and (6, 1280)(6,1280).
Phoenix [80]

Answer:

y=20(2)^x

Step-by-step explanation:

We want to write an exponential function that goes through the points (0, 20) and (6, 1280).

The standard exponential function is given by:

y=ab^x

The point (0, 20) tells us that <em>y</em> = 20 when <em>x</em> = 0. Hence:

20=a(b)^0

Simplify:

20=a(1)\Rightarrow a=20

So, our exponential function is now:

y=20(b)^x

Next, the point (6, 1280) tells us that <em>y</em> = 1280 when <em>x</em> = 6. Thus:

1280=20(b)^6

Solve for <em>b</em>. Divide both sides by 20:

64=b^6

Therefore:

b=\sqrt[6]{64}=2

Hence, our function is:

y=20(2)^x

8 0
2 years ago
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