It’s a little complicated but here’s how it works:
Imagine a table with the intervals
0:4 , 4:6 , 6:7 , 7:10 , 10:13 (10 year intervals)
Then we have different rows
Class width: 4 , 2 , 1 , 3 , 3
Freq density: 0.2 , 0.5 , 1.2 , 0.7 , 0.3
So now calculate frequency where freq = class width * density
Freq: 0.8 , 1 , 3.6 , 2.1 , 0.9
So to find median find cumulative frequency
(Add all freq)
Cfreq = 8.4 now divide by 2 = 4.2
So find the interval where 4.2 lies.
0.8 + 1 = 1.8 + 3.6 = 5.6
So 4.2 (median) will lie in that interval 60-70 years.
Answer:
(3)
Replcaing equation (3) into equation (2) we got:

And solving for Y we got:



And solving for X from equation (3) we got:

So we need 3L of orange juice with 25% of concentration and 17 L of orange juice with 5% of concentration
Step-by-step explanation:
For this problem we can work with the concentration of water and orange juice.
Let X the amount for the orange juice with 25% content and Y the amount for the orange juice with 5% of content
Using the concentration of orange juice we have:
(1)
And for the water we have:
(2)
If we solve for X from equation (1) we got:
(3)
Replcaing equation (3) into equation (2) we got:

And solving for Y we got:



And solving for X from equation (3) we got:

So we need 3L of orange juice with 25% of concentration and 17 L of orange juice with 5% of concentration
The sum of all the measurements is just the average times the number.


So if the average of all 92 is 7 the sum of those is

The average of the last two is 7.2 so their sum is

That means the sum of the first 90 is

so the average of the first 90 is

cm
Answer:

Step-by-step explanation:
We want to write an exponential function that goes through the points (0, 20) and (6, 1280).
The standard exponential function is given by:

The point (0, 20) tells us that <em>y</em> = 20 when <em>x</em> = 0. Hence:

Simplify:

So, our exponential function is now:

Next, the point (6, 1280) tells us that <em>y</em> = 1280 when <em>x</em> = 6. Thus:

Solve for <em>b</em>. Divide both sides by 20:

Therefore:
![b=\sqrt[6]{64}=2](https://tex.z-dn.net/?f=b%3D%5Csqrt%5B6%5D%7B64%7D%3D2)
Hence, our function is:
