3 years ago

Please help me with this question

Mathematics

1 answer:

rjkz [21]3 years ago

5 0

Answer:

Step-by-step explanation:

You might be interested in

2)[4] Let B, C, D be sets. Carefully prove: B (CUD) (BC) UD.

Lelu [443]

Answer:

mathematics is inclusive, so A or B is a set of things where each of them must be ... Kevin Houston in his book[2] gives an idea to think of a proof

Step-by-step explanation:

6 0

3 years ago

Movie ticket prices have been on a steady rise the past few years. Five years ago the ticket price was p = price. Two years ago

lbvjy [14]

The answer would be B) p+(2+1)

6 0

4 years ago

Read 2 more answers

Can some one solve this pls<img src="https://tex.z-dn.net/?f=%5Cint%5Climits%5E%5Cfrac%7B1%7D%7B%5Csqrt%7B2%7D%7D_0%20%5Cfrac%7B

zalisa [80]

Answer:

Step-by-step explanation:

Hello, please consider the following.

$x(t)=sin(t)\\\\dx=cos(t)dt\\\\\text{For x = }\dfrac{1}{\sqrt{2}}=\dfrac{\sqrt{2}}{2} \text{ we have } t = \dfrac{\pi}{4}$

So, we can write.

$\displaystyle \int\limits^{\dfrac{1}{\sqrt{2}}}_0 {\dfrac{1}{\sqrt{1-x^2}}} \, dx =\int\limits^{\dfrac{\pi}{4}}_0 {\dfrac{cos(t)}{\sqrt{1-sin^2(t)}}} \, dt\\\\=\int\limits^{\dfrac{\pi}{4}}_0 {\dfrac{cos(t)}{\sqrt{cos^2(t)}}} \, dt\\\\=\int\limits^{\dfrac{\pi}{4}}_0 {\dfrac{cos(t)}{cos(t)}} \, dt \\\\=\int\limits^{\dfrac{\pi}{4}}_0 {1} \, dt\\\\=\large \boxed{\sf \bf \dfrac{\pi}{4}}$