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3 years ago

Let x be a real number. Find the lowest possible value of |5x^2 - 16| + |10x - 2|.

1 answer:

4 0

Since the equations are for absolute value this means any negative number used the answer would become positive, so to get the lowest value possible x would need to equal 0, which would eliminate the x variable from the equations.

Replace x with 0 and solve:

|5(0)^2 - 16| + |10(0) - 2|

Simplify:

|0 - 16| + |0 - 2|

|-16| + |-2|

Combine:

|-18|

Absolute Value = 18

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Each of the walls of a room with square dimensions has been built with two pieces of sheetrock, a smaller one and a larger one.

azamat

To solve this problem you must apply the proccedure shown below:

1. You have the following information given in the problem above:

- The<span> room has square dimensions and it has been built with two pieces of sheetrock, a smaller one and a larger one.

2. Therefore, let's call

x: the smaller one.
y: the larger one.

3. Then, you have that the lenght of the wall is the sum of the smaller one and the larger one:

x+y

4. So, the area of the room is:

(x+y)(x+y)
(x+y)</span>²

Therefore, the answer is: (x+y)²

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3 years ago

Your mother has a new cell phone. It comes with 18 applications already installed. She uses only of those applications. She down

netineya [11]

"She uses only ___ of those applications"; Please provide the missing information

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3 years ago

11x+6y=-48 slope intercept

lesya [120]

Answer:

y = -11/6x - 8

Step-by-step explanation:

<u>Step 1: Solve for y</u>

11x + 6y = -48

11x + 6y - 11x = -48 - 11x

6y / 6 = (-48 - 11x) / 6

y = -8 - 11/6x

Answer: y = -11/6x - 8

5 0

3 years ago

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A projectile is launched from the ground at an angle of theta above the horizontal with an initial speed of v in ft/s. The rang

VARVARA [1.3K]

Answer:

$\theta=24.4^\circ$

Step-by-step explanation:

The formula you wrote has the fraction the other way around. You can find that the range of a projectile is in reality approximated by the equation $x=\frac{v^2}{g} sin(2\theta)=\frac{v^2}{32ft/s^2} sin(2\theta)$ , where we will use ft for distances.

From the given equation we have then $\frac{x32ft/s^2}{v^2} =sin(2\theta)$ , which means $\theta=\frac{Arcsin(\frac{x32ft/s^2}{v^2})}{2}$ since the arcsin is the inverse function of the sin.

Since we have x = 170 ft and v = 85 ft/s, we can substitute these values from the equation written, and we will have $\theta=\frac{Arcsin(\frac{(170ft)(32ft/s^2)}{(85ft/s)^2})}{2}$ , and from now on we have just to use a calculator, obtaining $\theta=\frac{Arcsin(0.75294117647)}{2}=\frac{48.84579804^\circ}{2}=24.4^\circ$

3 0

3 years ago

HELLLPPPP ASAP. Explain how to find the product of 3/8 x 7/9. Use complete sentences in your answer.

stiv31 [10]

Answer:

7/24

Step-by-step explanation:

you times the numerators together and times the denominators together then you simplify

5 0

3 years ago

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