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3 years ago

Somebody can help me with the final question

Mathematics

1 answer:

Sav [38]3 years ago

5 0

Answer:

Step-by-step explanation: the answer is c. you muptiply the top: 2 times 9 = 18 and you mutiply the bottom: 2x+3 times it turn out to be x(2x+3) then you mutiply that then you get your final answer which is C.

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How do you solve 4(4+363562-75635)(4)/53

Mice21 [21]

Simple, use PEMDAS and then do your simple math and then your answer should be 86922.56604

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3 years ago

What is the value of expression below?

Scilla [17]

Answer:

B)1.1

Step-by-step explanation:

I'm 100% sure

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3 years ago

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At noon, ship A is 130 km west of ship B. Ship A is sailing east at 25 km/h and ship B is sailing north at 20 km/h. How fast is

Hitman42 [59]

Answer:

answer = 12.87 km/h

Step-by-step explanation:

Given

Ship A is sailing east at 25 km/h = $\frac{dx}{dt}$

ship B is sailing north at 20 km/h = $\frac{dy}{dt}$

here x and y are the sailing at t = 4 : 00 pm for ship A and B respectively

so we get x = 4 ×25 =100 km/h

y = 4× 20 = 80 km/h

let z is the distance between the ships, we need to find $\frac{dz}{dt}$ at t = 4 hr

At noon, ship A is 130 km west of ship B (12:00 pm)

so equation will be

$z^2 = (130-x)^2 + y^2......................(i)\\put x = 100 and y = 80 \\\\we | | get \\$

$z^2 = 30^2 + 80^2\\z =\sqrt{7300} km/h$

derivative first equation w . r. to t we get

$2z\frac{dz}{dt} =$ $-2(130-x)\frac{dx}{dt}$ $+2y\frac{dy}{dt}$

$\frac{dz}{dt} =\frac{1}{z}[(x -130)\frac{dx}{dt} +y\frac{dy}{dt}]$

$\frac{dz}{dt} = \frac{( -20\times25 + 80\times20)}{\sqrt{7300} }$

$= \frac{1100}{85.44}\\ = 12.87km/h$

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3 years ago

Pls help question is on picture

brilliants [131]

Answer:

9/15 = 3/5 (simplified)

Step-by-step explanation:

In a right triangle, the cosine is the ratio of the adjacent side to the hypotenuse:

$\cos\theta = \frac{\text{adjacent}}{\text{hypotenuse}}$

The adjacent side is the side that makes up the angle but is not the hypotenuse.

I'm assuming the answer box should ask for cos(theta) rather than cos(x).

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3 years ago

What is the range of the given function

Lelechka [254]

Domain is X and Range is Y. So the range will be all the Y's which is the second answer

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3 years ago

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