Somebody can help me with the final question

Mathematics

1 answer:

Sav [38]3 years ago

5 0

Answer:

Step-by-step explanation: the answer is c. you muptiply the top: 2 times 9 = 18 and you mutiply the bottom: 2x+3 times it turn out to be x(2x+3) then you mutiply that then you get your final answer which is C.

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a hiking trail is 20 kilometers long. park organizers want to build 5 rest stops for hikers with one on each end of the trail an

ICE Princess25 [194]

The distance that will separate each rest stop is 4 kilometers.

<h3>What is the distance?</h3>

Division is the process of parting a number into equal parts using another number. The sign used to denote division is ÷. Division is one of the basic mathematical operations.

The distance = length of the trail / number of rest stops

20 km / 5 = 4km

To learn more about division, please check: brainly.com/question/13281206

#SPJ1

3 0

2 years ago

The mean SAT score in mathematics, M, is 600. The standard deviation of these scores is 48. A special preparation course claims

kupik [55]

Answer:

Step-by-step explanation:

The mean SAT score is $\mu=600$ , we are going to call it \mu since it's the "true" mean

The standard deviation (we are going to call it $\sigma$ ) is

$\sigma=48$

Next they draw a random sample of n=70 students, and they got a mean score (denoted by $\bar x$ ) of $\bar x=613$

The test then boils down to the question if the score of 613 obtained by the students in the sample is statistically bigger that the "true" mean of 600.

- So the Null Hypothesis $H_0:\bar x \geq \mu$

- The alternative would be then the opposite $H_0:\bar x < \mu$

The test statistic for this type of test takes the form

$t=\frac{| \mu -\bar x |} {\sigma/\sqrt{n}}$

and this test statistic follows a normal distribution. This last part is quite important because it will tell us where to look for the critical value. The problem ask for a 0.05 significance level. Looking at the normal distribution table, the critical value that leaves .05% in the upper tail is 1.645.

With this we can then replace the values in the test statistic and compare it to the critical value of 1.645.

$t=\frac{| \mu -\bar x |} {\sigma/\sqrt{n}}\\\\= \frac{| 600-613 |}{48/\sqrt(70}}\\\\= \frac{| 13 |}{48/8.367}\\\\= \frac{| 13 |}{5.737}\\\\=2.266\\$

<h3>since 2.266>1.645 we can reject the null hypothesis.</h3>