The correct formulae is CCl4
Answer:
Merlin's paper discusses two types of data: artifactual and paleoethnobotanical. Give specific examples of each and describe the sources of data and the ...
Answer:
d. pxp +2pq
Explanation:
The formula for genotype frequency for a population in Hardy-Weinburg equilibrium is as under:
p² + 2pq + q² = 1
where, p = dominant allele
q = recessive allele
Here,
p² represents frequency of homozygous dominant genotype
2pq represents frequency of heterozygous genotype
q² represents frequency of homozygous recessive genotype
Also, although the genotypes p² & 2pq are different from each other yet phenotypically they both will collectively produce dominant trait i.e. free ear lobes not attached earlobes. So the term "p² + 2pq or pxp + 2pq" represents the frequency of the individuals who show the dominant phenotype in this particular population. Dominant phenotype will comprise 75% of the population.
The somatic nervous system(SNS), autonomic nervous system (ANS), and entericnervous system (ENS). The portion of the peripheralnervous system consisting ofsomatic sensory (afferent) neurons and somatic motor (efferent) neurons.
