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3 years ago

Which point lies inside the circle with equation (x-2)^2+(y+3)^2=4

1 answer:

4 0

(x-h)^2+(y-k)^2=r^2

(h,k) is center
r=radius

(x-2)^2+(y-(-3))^2=2^2

center is (2,-3)
radius is 2

A. (2,-5) is on the circle, not inside
B. (2,-4) is inside
C. (0,-3) is on the circle, not inside
D. (2,0) is on the circle, not inside

answer is B

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Step-by-step explanation:

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3 years ago

A. 23.3 cm B. 16 cm C. 8 cm

Hitman42 [59]

B. 16 cm

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20x20=400

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3 years ago

Evaluate fog and gof if f(x)=5x-8 and g(x)= x^3

DerKrebs [107]

Answer:

see explanation

Step-by-step explanation:

note that f ○ g = f(g(x))

To evaluate substitute x = x³ into f(x)

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In the same way

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3 0

3 years ago

Which summation formula represents the series below? 1 + 2 + 6 + 24

krek1111 [17]

Question:

Which summation formula represents the series below? 1 + 2 + 6 + 24

(a) $\sum_{n=2}^{5}(n-1) !$

(b) $\sum_{n=0}^{3} n !$

(d) $\sum_{n=2}^{5} n !$

Answer:

Option a: $\sum_{n=2}^{5}(n-1) !$ is the correct answer.

Explanation:

Option a: $\sum_{n=2}^{5}(n-1) !$

By substituting the values of n and expanding the summation, we have,

$(2-1) !+(3-1) !+(4-1) !+(5-1) !$

Subtracting, we have,

$1 !+2!+3 !+4 !$

Expanding the factorial,

$1+(2*1)+(3*2*1)+(4*3*2*1)$

Simplifying, we get,

$1+2+6+24$

Thus, the summation $\sum_{n=2}^{5}(n-1) !$ represents the series $1+2+6+24$

Hence, Option a is the correct answer.

Option b: $\sum_{n=0}^{3} n !$

By substituting the values of n and expanding the summation, we have,

$0!+1!+2!+3!$

Expanding the factorial,

$0+1+(2*1)+(3*2*1)$

Simplifying, we get,

$0+1+2+6$

Thus, the summation $\sum_{n=0}^{3} n !$ does not represents the series $1+2+6+24$

Hence, Option b is not the correct answer.

Option c: $\sum_{n=1}^{4}(n+1) !$

By substituting the values of n and expanding the summation, we have,

$(1+1) !+(2+1) !+(3+1) !+(4+1) !$

Adding, we have,

$2!+3!+4!+5!$

Expanding the factorial,

$(2*1)+(3*2*1)+(4*3*2*1)+(5*4*3*2*1)$

Simplifying, we get,

$2+6+24+120$

Thus, the summation $\sum_{n=1}^{4}(n+1) !$ does not represents the series $1+2+6+24$

Hence, Option c is not the correct answer.

Option d: $\sum_{n=2}^{5} n !$

By substituting the values of n and expanding the summation, we have,

$2!+3!+4!+5!$

Expanding the factorial,

$(2*1)+(3*2*1)+(4*3*2*1)+(5*4*3*2*1)$

Simplifying, we get,

$2+6+24+120$

Thus, the summation $\sum_{n=2}^{5} n !$ does not represents the series $1+2+6+24$

Hence, Option d is not the correct answer.

Hence, the correct answer is Option a: $\sum_{n=2}^{5}(n-1) !$

6 0

3 years ago

2x+5+3x+6= combine like terms to simplify each expression

Oksi-84 [34.3K]

Answer:

5x +11

Step-by-step explanation:

5 0

3 years ago

Read 2 more answers