Which point lies inside the circle with equation (x-2)^2+(y+3)^2=4

1 answer:

4 0

(x-h)^2+(y-k)^2=r^2

(h,k) is center
r=radius

(x-2)^2+(y-(-3))^2=2^2

center is (2,-3)
radius is 2

A. (2,-5) is on the circle, not inside
B. (2,-4) is inside
C. (0,-3) is on the circle, not inside
D. (2,0) is on the circle, not inside

answer is B

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