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3 years ago

What is the name of the figure?

Mathematics

2 answers:

BartSMP [9]3 years ago

7 0

Answer:

Step-by-step explanation:

bogdanovich [222]3 years ago

6 0

Answer:

It is a rectangular pyramid

Step-by-step explanation:

The base is a rectangle. I hope this helps :)

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Emanuel is renting a car for 1week in Charleston, South Carolina. The rental car agency is charging $175 for the rental and 15%

Semenov [28]

Answer:

201.25 (im not 100% sure)

Step-by-step explanation:

If its correct please mark me as brainliest

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2 years ago

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If a line includes the points (8,0) and (20,12). What is its equation in slope-intercept form?

aev [14]

The slope-intercept form:

$y=mx+b$

m - slope

b - y-intercept

The formula of a slope:

$m=\dfrac{y_2-y_1}{x_2-x_1}$

substitute the coordinates of the points (8, 0) and (20, 12) to the formula:

$m=\dfrac{12-0}{20-8}=\dfrac{12}{12}=1$

y = 1x + b = x + b

Put the coordinates of the point (8, 0) to the equation of a line:

0 = 8 + b <em>subtract 8 from both sides</em>

-8 = b

<h3>Answer: y = x - 8</h3>

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3 years ago

A dilation is a nonrigid transformation that can produce enlarged or reduced images from a given pre-image. How do you know that

Marat540 [252]

A dilation can elongate or diminish a figure. It can create an image the same as the original by using a scale factor. The scale factor of a dilation is the ratio of corresponding side lengths. To dilate a polygon, multiply the coordinates of each vertex by the scale factor k and connect the vertices.

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3 years ago

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Consider the line integral Z C (sin x dx + cos y dy), where C consists of the top part of the circle x 2 + y 2 = 1 from (1, 0) t

pashok25 [27]

Direct computation:

Parameterize the top part of the circle $x^2+y^2=1$ by

$\vec r(t)=(x(t),y(t))=(\cos t,\sin t)$

with $0\le t\le\pi$ , and the line segment by

$\vec s(t)=(1-t)(-1,0)+t(2,-\pi)=(3t-1,-\pi t)$

with $0\le t\le1$ . Then

$\displaystyle\int_C(\sin x\,\mathrm dx+\cos y\,\mathrm dy)$

$=\displaystyle\int_0^\pi(-\sin t\sin(\cos t)+\cos t\cos(\sin t)\,\mathrm dt+\int_0^1(3\sin(3t-1)-\pi\cos(-\pi t))\,\mathrm dt$

$=0+(\cos1-\cos2)=\boxed{\cos1-\cos2}$

Using the fundamental theorem of calculus:

The integral can be written as

$\displaystyle\int_C(\sin x\,\mathrm dx+\cos y\,\mathrm dy)=\int_C\underbrace{(\sin x,\cos y)}_{\vec F}\cdot\underbrace{(\mathrm dx,\mathrm dy)}_{\vec r}$

If there happens to be a scalar function $f$ such that $\vec F=\nabla f$ , then $\vec F$ is conservative and the integral is path-independent, so we only need to worry about the value of $f$ at the path's endpoints.