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Roman55 [17]
2 years ago
12

Please help

Mathematics
1 answer:
bixtya [17]2 years ago
6 0

Answer:

41.4feet

Step-by-step explanation:

Using the SOH CAH TOA identity

Given the following

Distance of Rafael from the tower = 55feet = Adjacent

Angle of elevation = 37degrees

Required

Height of the tower = Opposite

Since Tan theta = opp/adj

Tan 37 = x/55

x = 55tan37

x = 55(0.7536)

x = 41.4

Hence the tower is 41.4feet up the viewing platform

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Find all missing angles.
Monica [59]
1=51
2=34
3= 95 (i think)
4=38
6 0
3 years ago
What is four over nine equal A over 45
QveST [7]
Answer: A = 20


How to Solve:

Just by looking at this problem I can tell that the denominators (9 an 45) are factors of 9. So the second equation is multiplied by 5 from the first equation.

4/9 x 5

4 x 5 = 20
— -—
9 x 5 = 45

So A would be 20.


Another way to solve this would be by multiplying the 1st equations numerator with the second equations denominator:

4 x 45 = 180

Then divide 180 with the 1st equation’s denominator.

180 / 9 = 20

A = 20
5 0
3 years ago
Which expression is equivilent to 6(3x-4)+2x
motikmotik

Answer:

44x,

Step-by-step explanation:

you can expand the brackets which equals 18x + 24 (or subtract 24 if the expression is 6(3x-4)) at the end of the equation you will add 2 which would give you 44x

4 0
2 years ago
Niña jumps 225 times in 3 minutes. At this rate how many times can she jump in 5 minutes
Tresset [83]
225/3 = 75
75 x 5 = 375

Hope this helps.
5 0
3 years ago
Read 2 more answers
The table displays the frequency of scores for a calculus class on an exam. The mean of the exam scores is 3.5. Score 1 2 3 4 5
vladimir1956 [14]

Answer:

f=11

Mode=4

Median=4

Explanation:

We are given that

a.Mean of the exam score,\bar x=3.5

Score(x)   frequency   C.F

1                  1                 1

2                  3                4

3                  f                 15(4+f=4+11)

4                  13               28

5                   4               32

\sum f_i=1+3+f+13+4=21+f

\sum f_ix_i=1(1)+2(3)+3(f)+4(13)+5(4)=1+6+3f+52+20=79+3f

(\bar x)=\frac{\sum f_ix_i}{\sum f_i}

Using the formula

3.5=\frac{79+3f}{21+f}

73.5+3.5f=79+3f

3.5f-3f=79-73.5

0.5f=5.5

f=\frac{5.5}{0.5}=11

b.Mode:The number which is repeat most times .

4 repeat most times

Hence, mode of all exam scores=4

N=32

N is even

Median=\frac{(\frac{n}{2})^{th}+(\frac{n}{2}+1)^{th}}{2}

Median=\frac{16th+17th}{2}=\frac{4+4}{2}=\frac{8}{2}=4

7 0
3 years ago
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