Answer:
(-1,-5)
Step-by-step explanation:
Starting at (0,0), we perform the first translation:
T<5,-7> implies that we move the point 5 units to the right (in the x (horizontal) direction), and 7 units DOWN in the y <vertical) direction.
From there we do the second translation: T<-6,2>
which means: 6 units to the left (in the horizontal direction) which takes us to "-1" for the x value, and 2 units up (vertical) which takes us to -5 for the y value.
Therefore the new location is (-1,-5)
2/3 is equivalent to 4/6. Other fractions are 6/9, or 8/12.
Beginning Balance: 820.64
Add:
donations: 500 + 55 + 25 580.00
Deduct:
electric bill: 40.64
postage bill: 12.75
rental : 445.00 <u> (498.39)</u>
Ending Balance 902.25
The balance at the end of the month is $902.25
option D is the correct option
y= 10- 2x
Now, if we take the first value of x i.e 1
then, y= 10-2(1)
= 10-2 = 8 ---------> this value matches with the given value of y
take,x =2
y=10-2(2) = 10-4 = 6--------->this value matches with the given value of y
taking, x = 3
y= 10-2(3) = 10- 6=4-------->this value matches with the given value of y
This is an exponential equation. We will solve in the following way. I do not have special symbols, functions and factors, so I work in this way
2 on (2x) - 5 2 on x + 4=0 =>. (2 on x)2 - 5 2 on x + 4=0 We will replace expression ( 2 on x) with variable t => 2 on x=t =. t2-5t+4=0 => This is quadratic equation and I solve this in the folowing way => t2-4t-t+4=0 => t(t-4) - (t-4)=0 => (t-4) (t-1)=0 => we conclude t-4=0 or t-1=0 => t'=4 and t"=1 now we will return t' => 2 on x' = 4 => 2 on x' = 2 on 2 => x'=2 we do the same with t" => 2 on x" = 1 => 2 on x' = 2 on 0 => x" = 0 ( we know that every number on 0 gives 1). Check 1: 2 on (2*2)-5*2 on 2 +4=0 => 2 on 4 - 5 * 4+4=0 => 16-20+4=0 =. 0=0 Identity proving solution.
Check 2: 2 on (2*0) - 5* 2 on 0 + 4=0 => 2 on 0 - 5 * 1 + 4=0 =>
1-5+4=0 => 0=0 Identity provin solution.
