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Phoenix [80]
2 years ago
11

A businessman bought a personal computer for $10,768. Calculate the selling price of the personal computer if he made a profit o

f 12 percentage​
Mathematics
2 answers:
Maksim231197 [3]2 years ago
5 0

Answer:

$12,060

Step-by-step explanation:

LET selling price be rep by x

since he made a profit of 12%, we then add to 100%

100% + 12% = 112%.

to find the selling price, we multiply cost price  by 112%

112% x $10768 =

112 / 100  x $10,768

=  1.12 x $10,768  = 12,060

selling price = $12,060.

Luden [163]2 years ago
5 0

Answer:

12060.16

Step-by-step explanation:

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The area of a rhombus is 72 m2. One<br> diagonal is 18m. Find the other diagonal.
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Other diagonal is 8 m

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2 years ago
To estimate the mean height μ of male students on your campus,you will measure an SRS of students. You know from government data
nexus9112 [7]

Answer:

a) \sigma = 0.167

b) We need a sample of at least 282 young men.

Step-by-step explanation:

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by

Z = \frac{X - \mu}{\sigma}

This Zscore is how many standard deviations the value of the measure X is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

(a) What standard deviation must x have so that 99.7% of allsamples give an x within one-half inch of μ?

To solve this problem, we use the 68-95-99.7 rule. This rule states that:

68% of the measures are within 1 standard deviation of the mean.

95% of the measures are within 2 standard deviations of the mean.

99.7% of the measures are within 3 standard deviations of the mean.

In this problem, we want 99.7% of all samples give X within one-half inch of \mu. So X - \mu = 0.5 must have Z = 3 and X - \mu = -0.5 must have Z = -3.

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Z = \frac{X - \mu}{\sigma}

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(b) How large an SRS do you need to reduce the standard deviationof x to the value you found in part (a)?

You know from government data that heights of young men are approximately Normal with standard deviation about 2.8 inches. This means that \sigma = 2.8

The standard deviation of a sample of n young man is given by the following formula

s = \frac{\sigma}{\sqrt{n}}

We want to have s = 0.167

0.167 = \frac{2.8}{\sqrt{n}}

0.167\sqrt{n} = 2.8

\sqrt{n} = \frac{2.8}{0.167}

\sqrt{n} = 16.77

\sqrt{n}^{2} = 16.77^{2}

n = 281.23

We need a sample of at least 282 young men.

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