Answer:
the equation of the line that is perpendicular to y = 1/2x + 3 and passes through the point (10, -5)
= -5 = -2x + 15
Step-by-step explanation:
Write an equation of the line that is perpendicular to y = 1/2x + 3 and passes through the point (10, -5).
Using the slope intercept equation,
y = mx +c
m = slope = 1/2
For two lines to be perpendicular, the product of their slopes is -1
Let the slope of the other line be m2
m1×m2 =-1
1/2×m2 = -1
m2 = -1/(1/2) = -2
Slope of line = -2
For points (10, -5), x = 10, y =-5
-5 = -2× 10 +c
-5 = -20+ c
c = -5+20= 15
the equation of the line that is perpendicular to y = 1/2x + 3 and passes through the point (10, -5)
-5 = -2x + 15
Answer:log₂(

)
Explanation:Before we begin, remember the following:logₐ(x) - logₐ(y) = logₐ(

)
alog(x) = log(xᵃ)
Now, for the given we have:3 log₂(x) - (log₂3 - log₂(x+4))
log₂(x²) - log₂(

)
log₂(

) = log₂(

)
Hope this helps :)
Answer:
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Step-by-step explanation:
Answer: 271.0638298 is - 8,- 3
Step-by-step explanation:
-3y<2+ +18=