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klio [65]
2 years ago
11

Find the distance between the pair of points. (-7,4) and (2,-5)

Mathematics
1 answer:
frez [133]2 years ago
5 0

Answer:

length =  \sqrt{ {(x _{2}  - x _{1} ) {}^{2}  + (y _{2} - y _{1} )}^{2} }  \\  =  \sqrt{ {(2 - ( - 7))}^{2} +  {( - 5 - 4)}^{2}  }  \\  =  \sqrt{ {9}^{2}  +  {( - 9)}^{2} }  \\  =  \sqrt{81 + 81}  \\  \sqrt{162}  \\  = 12.7 \: units

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1 5/7÷4/9 = what's the answer and how to write the problem out
balu736 [363]

The solution to given expression 1\frac{5}{7} \div \frac{4}{9} is \frac{27}{7} or 3.8571

<em><u>Solution:</u></em>

Given expression is:

1\frac{5}{7} \div \frac{4}{9}

<em><u>First let us convert the mixed fraction to improper fraction</u></em>

Multiply the whole number by the denominator.

Add the answer from Step 1 to the numerator.

Write answer from Step 2 over the denominator.

Thus we get,

1\frac{5}{7} = \frac{1 \times 7 + 5}{7} = \frac{12}{7}

Now the given expression becomes,

1\frac{5}{7} \div \frac{4}{9} = \frac{12}{7} \div \frac{4}{9}

Convert the problem to multiplication by changing the division sign to multiplication and inverting the fraction to the right of the sign

\frac{12}{7} \div \frac{4}{9} = \frac{12}{7} \times \frac{9}{4}

Multiply the numerators, multiply the denominators, and leave the product in factored form

\frac{12}{7} \times \frac{9}{4} = \frac{27}{7}

In decimal form we get,

\frac{27}{7} = 3.8571

Thus the solution to given expression is \frac{27}{7} or 3.8571

4 0
2 years ago
Can you help me with this
AlladinOne [14]
The answer is C
5/12= 0.4167
the product is 2.9
5/12< 2.9 <7
4 0
3 years ago
Read 2 more answers
The straight line joining the points A(3,-5) and B(6,k) has a gradient of 4. Work out the value of k.
BaLLatris [955]

The straight line joining the points A(3,-5) and B(6,k) has a gradient of 4.

Gradient is the slope

So the slope of the line joining the points A(3,-5) and B(6,k) is 4

Slope of line joining two points = \frac{y_2-y_1}{x_2-x_1}

A(3,-5) and B(6,k) are (x1,y1)  and (x2,y2)

slope = \frac{y_2-y_1}{x_2-x_1}

slope = \frac{k-(-5)}{6-3}=\frac{k+5)}{3}

We know slope =4

 \frac{k+5)}{3}=4

Cross multiply  and solve for k

k + 5 = 12

k = 7

The value of k = 7

7 0
2 years ago
Solve the following equation for y.<br>x-5y=-18<br>​
olganol [36]

Answer:

y=15x+185

Step-by-step explanation:

Step 1: Add -x to both sides.

x−5y+−x=−18+−x

−5y=−x−18

Step 2: Divide both sides by -5.

−5y−5=−x−18−5

y=15x+185

6 0
2 years ago
Please help ASAP !!!!!
zloy xaker [14]

Answer:

i need points im really sorry

Step-by-step explanation:

7 0
3 years ago
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