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Serhud [2]
3 years ago
14

What is the y-intercept of the line whose equation is y = –2x + 8?​

Mathematics
1 answer:
g100num [7]3 years ago
3 0

Answer:

(0,8)

Step-by-step explanation:

y = –2x + 8

The y intercept is found when x =0

y = –2*0 + 8

y = 8

The y intercept is

(0,8)

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Answer:

i think the second one

Step-by-step explanation:

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3 years ago
Given that 2y^3+by-cy+d,where b,c and d are constants,leaves a remainder R when divided by (y+1) , (y-2) and (2y-1). Find the va
Eddi Din [679]

The polynomial remainder theorem says that a polynomial <em>p(x)</em> leaves a remainder of <em>p(k)</em> when it's divided by <em>x</em> - <em>k</em>.

We're given that dividing <em>p(y)</em> = 2<em>y</em>³ + <em>by</em>² - <em>cy</em> + <em>d</em> leaves the same remainder <em>R</em> after dividing it by <em>y</em> + 1, <em>y</em> - 2, and 2<em>y</em> - 1. So we have

<em>p</em>(-1) = 2(-1)³ + <em>b</em>(-1)² - <em>c</em>(-1) + <em>d</em> = <em>R</em>

==>  <em>R</em> = -2 + <em>b</em> + <em>c</em> + <em>d</em>

<em>p</em>(2) = 2(2)³ + <em>b</em>(2)² - <em>c</em>(2) + <em>d</em> = <em>R</em>

==>  <em>R</em> = 16 + 4<em>b</em> - 2<em>c</em> + <em>d</em>

<em>p</em>(1/2) = 2(1/2)³ + <em>b</em>(1/2)² - <em>c</em>(1/2) + <em>d</em> = <em>R</em>

==>  <em>R</em> = 1/4 + <em>b</em>/4 - <em>c</em>/2 + <em>d</em>

<em />

We're also given that <em>y</em> + 2 is a factor, which means dividing <em>p(y)</em> by it leaves no remainder, and so

<em>p</em>(-2) = 2(-2)³ + <em>b</em>(-2)² - <em>c</em>(-2) + <em>d</em> = 0

==>  0 = -16 + 4<em>b</em> + 2<em>c</em> + <em>d</em>

<em />

Solve the system of equations in boldface. You can eliminate <em>d</em> from the first 3 to first solve for <em>b</em> and <em>c</em>, then solve for <em>d</em> :

(-2 + <em>b</em> + <em>c</em> + <em>d</em>) - (16 + 4<em>b</em> - 2<em>c</em> + <em>d</em>) = <em>R</em> - <em>R</em>

-18 - 3<em>b</em> + 3<em>c</em> = 0

<em>b</em> - <em>c</em> = -6

(-2 + <em>b</em> + <em>c</em> + <em>d</em>) - (1/4 + <em>b</em>/4 - <em>c</em>/2 + <em>d</em>) = <em>R</em> - <em>R</em>

-9/4 + 3<em>b</em>/4 + 3<em>c</em>/2 = 0

<em>b</em> + 2<em>c</em> = 3

(<em>b</em> - <em>c</em>) - (<em>b</em> + 2<em>c</em>) = -6 - 3

-3<em>c</em> = -9

<em>c</em> = 3

<em>b</em> - 3 = -6

<em>b</em> = -3

-16 + 4(-3) + 2(3) + <em>d</em> = 0

<em>d</em> = 22

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3 years ago
PLEASE HELP WITH QUESTIONS 4 AND 5
agasfer [191]

Answer:

4 - Complementary

5 - Supplementary

Step-by-step explanation:

i can't find the value of X

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3 years ago
WILL MARK BRAINLIEST
Levart [38]

Answer:

Part 1:

The solution set of the system of equations is x = 1, y = 1

Part 2:

The solution set is x = 1, y = 1

Part 3:

The similarity of the system of equations in Parts 1 and 2 is that they have the same solution set

The difference of the system of equations in Parts 1 and 2 is that they are arranged differently

Step-by-step explanation:

Part 1:

The system of equation is given as follows;

2·x + y = 3...(1)

x = 2·y - 1...(2)

The above system of equations can be written in terms of the variable, y, as follows;

For equation (1), we have;

y = 3 - 2·x

For equation (2), we have;

y = (x + 1)/2

From the attached graph created with Microsoft Excel, we have;

The solution set (the point of intersection) of the system of equations is x = 1, y = 1

To accurately find the common solution, we have;

(x + 1)/2 = 3 - 2·x

x + 1 = 2·(3 - 2·x) = 6 - 4·x

x + 1 = 6 - 4·x

x + 4·x = 6 - 1

5·x = 5

x = 5/5 = 1

x = 1

Therefore, y = 3 - 2·x = 3 - 2× 1 = 1, at the common solution

Part 2:

y = -2x + 3

x - 2y = -1

∴ x = 2y -1

y = -2(2y -1) + 3

y = -4y + 2 + 3

5y = 5

y = 1

x = 2y - 1 = 2 - 1 = 1

x = 1

The solution set is x = 1, y = 1

Part 3

The system of equations are similar in terms of their solution

The system of equations are different in terms of their arrangement

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2 years ago
Help!!!!!!!!!!!!!!!!!!!
nalin [4]

no clue, man. sorry. i really wish i understood it so i could help you

3 0
3 years ago
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