So to start you will need to divide by -5 then -5 divided by -5 cancelle
We are given equations as

Firstly, we will write in slope intercept form of line
y=mx+b

Subtract both sides by 4x


now, we can divide both sides by a

we can find slope
so, we get

we are given second equation as

Firstly, we will write in slope intercept form of line
y=mx+b
divide both sides by a

we can find slope

we are given both lines are perpendicular
so, the multiplication of their slopes must be -1

we can plug values

now, we can solve for a

Multiply both sides by a


now, we can solve for a
we get
...............Answer
Answer:
A quadratic condition is a condition of the subsequent degree, which means it contains, in any event, one term that is squared. The standard structure is ax² + bx + c = 0 with a, b, and c being constants, or mathematical coefficients, and x is an obscure variable.
The phase shift is 7.2 right