Answer:
The next two numbers are -7500 and 37500
Step-by-step explanation:
To find the pattern, divide any number by the previous.
-300/60 = -5.
Meaning they are being multiplied by -5, so we can just multiply this to the last number.
1500 * -5 = -7500,
-7500 * -5 = 37500.
Answer:
The third term is -25.
Step-by-step expanation:
d(1)=3
From this equation, we know the first term is 3.
d(n)=d(n−1)−14
This looks like a recursive formula. It is used to find the next term.
n is the variable for the term number that you are solving for.
d(n-1) is the term value before the what you are looking for.
To find the 2nd term, use the formula and substitute values known:
d(n)= d(n−1)−14
d(2) = d(2-1) - 14
d(2) = d(1) - 14
We know d(1)=3
d(2) = 3 - 14
d(2) = -11
Find the third term using the same method:
d(n) = d(n−1)−14
d(3) = d(3−1)−14
d(3) = d(2)−14
d(3) = -11 - 14
d(3) = -25
Alright, here goes:
For this question, you are asked about the median and Interquartile Range(IQR), so first you need to understand what that means.
The IQR is the box in the middle of the box-and-whisker-plot. The question asks for the place to have a small IQR, so the most likely places are Pensacola and Jacksonville.
The question is also asking for a high median temperature. The median is the line in the middle of the plot.
The median of Pensacola's plot is higher than the median of Jacksonville, so Pensacola Beach is your answer :)
Answer:
See below
Step-by-step explanation:
4(x + 5) = 9x + 4x − 34
4x + 20 = 9x + 4x − 34 [Distributive]
4x + 20 = 13x − 34 {Combine Like Terms]
4x - 13x + 20 = 13x - 13x − 34 [Subtractive: -13x both sides]
-5x + 20 = - 34 [Combine Like Terms]
-5x + 20 - 20 = -34 - 20 [Subtractive: - 20 both sides]
-5x = -54 [Combine Like Terms]
x = -54/-5 [Division Property: divide both sides by -5]
x = - 10 4/5
Answer:
Step-by-step explanation:
The question is not biased. It doesn't push the participants to answer one way or another.
However, the sample is biased. It does not represent the population.
The first and fourth options are correct.
