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2 years ago

Which function is undefined when Theta = StartFraction pi Over 2 EndFraction radians? cos Theta cot Theta csc Theta tan Theta.

Mathematics

1 answer:

Alex Ar [27]2 years ago

7 0

Answer: ###########

Step-by-step explanation:

YW :)

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The scale on a map shows that 5 centimeters=2 kilometers.

stiks02 [169]

PART A. Answer: 12.5 cm. Explanation. For every 2 kilometers, there are 5 centimeters. 5 kilometers is 2.5 times more than 2 kilometers. So you multiply 5 centimeters by 2.5 and that is the answer.

PART B Answer: .8 km. Explanation. If you divide 5cm by 2, you get 2.5. So divide 2km by 2.5 and that is how you get .8.

4 0

3 years ago

Read 2 more answers

In the following diagram line C intersects line D. Using complete sentences, classify the relationship between <7 and <8 c

Softa [21]

Answer:

sorry wish i knew to need the answer also

Step-by-step explanation:

3 0

3 years ago

Any help would be appreciated. Thank you!

trapecia [35]

Answer:

Area $=62.5\sqrt{6}$ square units

$AB=5\sqrt{15}$ units

$BC=5\sqrt{10}$ units

Step-by-step explanation:

In a right triangle the altitude drawn to the hypotenuse is the geometric mean of the segments at which this altitude divides the hypotenuse.

So,

$BD^2=15\cdot 10\\ \\BD^2=150\\ \\BD=\sqrt{150}=5\sqrt{6}\ units$

a. The area of the triangle ABC is

$A_{ABC}=\dfrac{1}{2}\cdot BD\cdot AC=\dfrac{1}{2}\cdot 5\sqrt{6}\cdot (15+10)=\dfrac{125\sqrt{6}}{2}=62.5\sqrt{6}\ un^2.$

b. The legs of the right triangle are geometric means of the segment adjacent to this leg and the hypotenuse, so

$AB^2=AD\cdot AC=15\cdot 25\Rightarrow AB=5\sqrt{15}\ units\\ \\BC^2=CD\cdot AC=10\cdot 25\Rightarrow BC=5\sqrt{10}\ units$

5 0

3 years ago

Car A travels 20 mph faster than Car B. In the same time that Car A travels 252 miles, Car B travels 196 miles. Find their speed

RoseWind [281]

<u>Answer:</u>

A = 70

B = 90

<u>Step-by-step explanation:</u>

We know that Car A travels 20 mph faster than Car B.

Assuming the speed of Car B to be x and the speed of Car A to be x+20, we can write:

$\frac{196}{x} =\frac{252}{x+20}$

Taking the reciprocal of both sides to make x the subject:

$196(x+20)=252x$

$196x+3920=252x$

$252x-196x=3920$

$56x=3920$

$x=70$ ---> speed of Car A

Finding the speed of Car B: $x+20 = 70+20=90$

Therefore, the speed of Car A = 70 and the speed of Car B = 90.

8 0

3 years ago

Please help me please !!

Artist 52 [7]

The range is: 35-60
The IQR is: 11
This value is the first 25%

IQR= interquartile range

Hope this helps ;)

5 0

3 years ago