Which function is undefined when Theta = StartFraction pi Over 2 EndFraction radians? cos Theta cot Theta csc Theta tan Theta.

The figure shows ∠AOC drawn with a protractor. What type of angle is it and what is its measure?

Debora [2.8K]

Answer:

the answer is acute 35.

Step-by-step explanation:

3 0

3 years ago

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A study of long-distance phone calls made from General Electric Corporate Headquarters in Fairfield, Connecticut, revealed the l

Anna [14]

Answer:

a) 0.4452

b) 0.0548

c) 0.0501

d) 0.9145

e) 6.08 minutes or greater

Step-by-step explanation:

We are given the following information in the question:

Mean, μ = 4.7 minutes

Standard Deviation, σ = 0.50 minutes.

We are given that the distribution of length of the calls is a bell shaped distribution that is a normal distribution.

Formula:

$z_{score} = \displaystyle\frac{x-\mu}{\sigma}$

a) P(calls last between 4.7 and 5.5 minutes)

$P(4.7 \leq x \leq 5.5) = P(\displaystyle\frac{4.7 - 4.7}{0.50} \leq z \leq \displaystyle\frac{5.5-4.7}{0.50}) = P(0 \leq z \leq 1.6)\\\\= P(z \leq 1.6) - P(z$

$P(4.7 \leq x \leq 5.5) = 44.52\%$

b) P(calls last more than 5.5 minutes)

$P(x > 5.5) = P(z > \displaystyle\frac{5.5-4.7}{0.50}) = P(z > 1.6)\\\\P( z > 1.6) = 1 - P(z \leq 1.6)$

Calculating the value from the standard normal table we have,

$1 - 0.9452 = 0.0548 = 5.48\%\\P( x > 5.5) = 5.48\%$

c) P( calls last between 5.5 and 6 minutes)

$P(4.7 \leq x \leq 5.5) = P(\displaystyle\frac{5.5 - 4.7}{0.50} \leq z \leq \displaystyle\frac{6-4.7}{0.50}) = P(1.6 \leq z \leq 2.6)\\\\= P(z \leq 2.6) - P(z$

$P(5.5 \leq x \leq 6) = 5.01\%$

d) P( calls last between 4 and 6 minutes)

$P(4 \leq x \leq 6) = P(\displaystyle\frac{4 - 4.7}{0.50} \leq z \leq \displaystyle\frac{6-4.7}{0.50}) = P(-1.4 \leq z \leq 2.6)\\\\= P(z \leq 2.6) - P(z$

$P(4 \leq x \leq 6) = 91.45\%$

e) We have to find the value of x such that the probability is 0.03.

P(X > x)

$P( X > x) = P( z > \displaystyle\frac{x - 4.7}{0.50})=0.03$

$= 1 -P( z \leq \displaystyle\frac{x - 4.7}{0.50})=0.03$

$=P( z \leq \displaystyle\frac{x - 4.7}{0.50})=0.997$

Calculation the value from standard normal z table, we have,

P(z < 2.75) = 0.997

$\displaystyle\frac{x - 4.7}{0.50} = 2.75\\x = 6.075 \approx 6.08$

Hence, the call lengths must be 6.08 minutes or greater for them to lie in the highest 3%.

8 0

3 years ago

Write the equation of the line perpendicular to y = x+ 5 that passes through the point ( -7,3).

Burka [1]

Answer:

y = - x - 4

Step-by-step explanation:

A line perpendicular to the line: y = x + 5

must have a slope that is the "opposite of the reciprocal" of the slope of the given line. Then the slope of the perpendicular line must be "-1".

Now that we know the slope of the perpendicular line, we use the point (-7, 3) to complete the equation of the line:

y = -1 x + b

3 = -1 (-7) + b

then we solve for "b":

3 = 7 + b

3 - 7 = b

b = -4

Now we can write the total equation of the perpendicular line in slope-intercept form as:

y = - x - 4

3 0

3 years ago

Find the equation of the line passing through the given points. Express the equation in standard form.

Artyom0805 [142]

We want to write the equation of the line passing through these two points in standard form.

First, we are going to do this in slope intercept form and then change the form to standard form, which is Ax + By = C

We will use the equation y = mx + b, and since we are given two points on the line we are going to determine the slope of the line by determining the change in the y coordinates

m = y sub2 - y sub1 divided by the change in the X coordinates x sub2 – x sub1

We will start by determining the slope

(1, -6) the 1 is x sub 1 and the 6 is y sub 1

(-7, 2) the -7 is x sub 2 and the 2 is y sub 2

2 - (-6) = 8

-7 -1 = -8

so equation now is m = -1

So now again referring back to the slope intercept of the line we now know y = -1 + b. We still have to determine b and the y intercept, and we can do this by using one of the given points and substituting in the value for y and x, and then solve for b. Since these points are on the line, they must satisfy this equation. If we use the first coordinates, we would substitute 1 for x and -6 for y.

-6 = -1 times x, which is 1 + b

b = -5

construct the line equation y = mx + b where m = -1 & b = -5

In slope intercept form the equation would be y = -x - 5

Now we want to write this in standard form now. We have to deal with two things. The x and y terms have to be on the left side and A and B and C have to be integers.

The standard form of a linear equation is Ax + By=CA x + By = C . Move all terms containing variables to the left side of the equation.

Add x to both sides of the equation.

y + x = -5

Reorder y & x

x + y = -5

3 0

4 years ago

In quadrilateral ABDC, AB ∥ CD. Which additional piece of information is needed to determine that ABDC is a parallelogram? AB ≅

siniylev [52]

For any quadrilateral to be a parallelogram

i) either both the pairs of opposite sides must be equal

ii) Both the pairs of opposite sides must be parallel

iii) Opposite pairs of angles must be equal

iv) Diagonals must bisect each other.

v) A pair of opposite sides must be parallel and equal

Here we are already given that AB || CD

So either we should be given that AD || BC

or we must be given that AB = CD

Here it is given AB = CD as an option.

So Option A) or the first option is the right answer that AB ≅CD is needed to prove ABCD is a parallelogram.

7 0

4 years ago

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