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Step2247 [10]
3 years ago
7

What algebraic property is demonstrated in the equation below? 5(8x-4)-10=40x-20-10

Mathematics
1 answer:
grandymaker [24]3 years ago
3 0
Distributive Property
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Explain why 1/12 + 1/2= 7/12
valentina_108 [34]

Answer:

1/12 + 1/2 = 1/12 + 6/12 - 1+6/12 = 7/12

Step-by-step explanation:

hope this makes sense

4 0
3 years ago
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Maribel wants to skate 12 miles on Monday. If she skates io mile Monday morning and į of that distance Monday afternoon, will sh
Alex17521 [72]

Answer & Step-by-step explanation:

Yes, Maribel will reach her goal. If you convert each fraction with a denominator of 6 then add it up, it will be 1 7/6 which is equal to 2 1/6.

I hope this helps ;)

5 0
2 years ago
U is the set of integers. G is the set of negative integers. What is the complement of set G in universive U?
harina [27]

Answer:

Wouldn't the answer be C) Positive Integers?

Step-by-step explanation: Because the complement of a set include all of the elements not included in the indicated set. I hope I'm making some sense. :)

6 0
3 years ago
GIVING BRAINLIEST IF CORRECT PLEASE HELP ASA[P
Vitek1552 [10]

Answer:

A) b= 8 students

B)  1) 19/55   2) 28/55

Step-by-step explanation:

I'm sorry if I'm getting this whole concept wrong cause it felt way too easy to be right so I'm sorry if you get it wrong.

The reason the first question is 8 is because of the fact that you first have to add the students charted on the Venn-diagram and subtract that from 55, getting you to 8 students.

For the second one, the first part would be 19/55 becuase in the Venn-diagram it is shown that only 19 people passed both and so that be the numerator and the denominator would be the total of students, so it would be 55.

Same thing for part two except the fact that you have to add the students who only passed one subject, so combine 17 and 11, getting you to 28, thus getting the answer 28/55.  

3 0
3 years ago
Help thankss <br>answer is <br><img src="https://tex.z-dn.net/?f=%20%28%20-%2014.0%29" id="TexFormula1" title=" ( - 14.0)" alt="
lyudmila [28]
We have point P=(x_0,y_0)=(2,-4), so first calculate f'(x_0). There will be:

y=f(x)=2x^3-5x^2\\\\\\\\f'(x)=\big(2x^3-5x^2\big)'=\big(2x^3\big)'-\big(5x^2\big)'=2\big(x^3\big)'-5\big(x^2\big)'=\\\\=2\cdot3x^2-5\cdot2x=\boxed{6x^2-10x}\\\\\\\\f'(x_0)=f'(2)=6\cdot2^2-10\cdot2=6\cdot4-20=24-20=\boxed{4}

Now, we can write the equation of the normal line as:

y-y_0=-\dfrac{1}{f'(x_0)}(x-x_0)\\\\\\ y-(-4)=-\dfrac{1}{4}(x-2)\\\\\\y+4=-\dfrac{1}{4}x+\dfrac{1}{2}\\\\\\y=-\dfrac{1}{4}x+\dfrac{1}{2}-4\\\\\\\boxed{y=-\dfrac{1}{4}x-\dfrac{7}{2}}

Normal line (and every line) crosses x-axis when y = 0, so coordinates of A:

\boxed{y=0}\qquad\qquad\text{and}\\\\\\y=-\dfrac{1}{4}x-\dfrac{7}{2}\\\\\\&#10;0=-\dfrac{1}{4}x-\dfrac{7}{2}\\\\\\\dfrac{1}{4}x=-\dfrac{7}{2}\quad|\cdot4\\\\\\x=-\dfrac{7\cdot4}{2}\\\\\\x=-7\cdot2\\\\\\\boxed{x=-14}\\\\\\\boxed{A=(-14,0)}
8 0
3 years ago
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