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andrezito [222]
2 years ago
9

Andrew has $2.00 in quarters in his pocket, including three state quarters. He takes two quarters out of his pocket. What is the

probability that they are not state quarters?
A 3/8
B 5/8
C 3/14
D 5/14
Show work please!
Mathematics
1 answer:
Zolol [24]2 years ago
8 0
$2.00 in quarters is 8 quarters, since 1 quarter is 25 cents.
Out of those 8 quarters, only 3 are state quarters.
That means 5 are not state quarters.
So there is a 5/8 chance that the first quarter he takes out is not a state quarter.
If it is not, then there are 3 state quarters and 7 total quarters left, which means a 4/7 chance that the second quarter is not a state quarter.
To find the probability of both of these quarters not being state quarters, multiply the probabilities by each other.
4/7 • 5/8 = 20/56
Now simplify:
20/56 = 10/28 = 5/14
5/14 is in simplest form, so it is the answer.
So the answer is D. 5/14.
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Step-by-step explanation:

Lets assume that angle of right angle trangles are <a,<b and <c

here one of the angle is 90°

so, <a=90°

now,

By the question

<c=3×<b+14

again,

<a+<b+<c=180° (being sum of interior angles of trangles)

90°+<b+(3×<b+14)=180° ( including the value of <a and <c)

90°+<b+3<b+14=180°

4<b=180-90-14

<b=86/4

<b=19°

<c=3×<b+14

=3×19+14

<c=71

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3 years ago
Help guys<br>make p da subject of the formula<br>​
Basile [38]

Answer:

p=\dfrac{m}{k-s}

Step-by-step explanation:

When they ask you to make a variable the "subject of the formula", they're basically asking you to build a "machine" for it. In the expression y=mx+b, for instance, if we know what m, x, and b are, we can plug them all in and out comes a value for y! To build that machine, we need to get it by itself on one side of the equation.

So, we want to build this machine for p, and the equation we have to build it out of is

1=\dfrac{pk}{m+sp}

One think we can immediately say about this equation: for a fraction to be equal to one, its numerator and denominator have to be equal to each other. So we can say

m+sp=pk

Ok, what next? Well, if we want p by itself, we need to somehow peel it off of that <em>sp</em> and <em>pk</em>. Let's collect them on the right side by subtracting <em>sp </em>from both sides:

m=pk-sp

p is a <em>common factor</em> of both <em>sp </em>and <em>pk</em>, so we can peel it away using the distributive property:

m=p(k-s)

And from here, we can divide both sides by k-s and we'll have p as our subject:

\dfrac{m}{k-s}=p or p=\dfrac{m}{k-s}

So if we know m, k, and s, we can easily solve for p. If m = 4, k = 2, and s = 0:

p=\frac{4}{2-0} =\frac{4}{2}=2

3 0
2 years ago
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melamori03 [73]

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6 0
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Answer:

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Step-by-step explanation:

A-2+3=-2

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So, A-2+3=-2 is now -3-2+3=-2

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Step-by-step explanation:

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