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Olin [163]
3 years ago
8

You give 1/3 of a pan of brownies to Susan and 1/6 of the pan of brownies to Patrick. How much of the pan of brownies did you gi

ve away?
Pam walks 7/8 of a mile to school. Paul walks 1/2 of a mile to school. How much farther does Pam walk than Paul?

Tom bought 2 1/4 kilograms of bananas and 1 1/3 kilograms of grapes. How many kilograms of fruit did Tom buy in all?
Mathematics
1 answer:
Levart [38]3 years ago
5 0

Answer:

1) 1/2 pan

2) 3/8 mile

3) 3 7/12 kg

Step-by-step explanation:

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The price of a bracelet is $1.29. If the tax rate is 5%, find the total cost of<br> the bracelet
Salsk061 [2.6K]

Answer: $1.35

Step-by-step explanation:

1.29 * 5% = 1.29 * 0.05 = 0.0645

0.0645 rounds down to 0.06

1.29 + 0.06 = 1.35

3 0
3 years ago
----- is 10 times as much as 53
Kobotan [32]

Answer:

I think it's right answer is 530

4 0
3 years ago
Tell weather the given value is a solution of the inequality
natta225 [31]
Yes, 8 is a solution

r - 3 ≤ 9; r  = 8

plug in 8 to r

(8) - 3 ≤ 9
5 ≤ 9 (true)

hope this helps
4 0
3 years ago
Read 2 more answers
17. Write interval notation for the given graph.
Volgvan

Answer:

<u>D</u>

Step-by-step explanation:

The interval notation for the graph :

  • -5 ≤ x ≤ 7
  • <u>[5, 7]</u>
7 0
2 years ago
Read 2 more answers
To solve problems about spans of time that include B.C. and A.D. dates, you would need to use which numbers?
Studentka2010 [4]

The correct numbers to use in solving problems about spans of time like B.C. and A.D. should be “integers”.

Integers are whole numbers (not a fractional number or not a decimal number) which can take a value of negative, zero, or positive number. Example of integers would be -1, 0 and 1.

<span>In calculations, the time period would be on the x-axis. Since B.C. and A.D. are two different spans of time, therefore in the calculations, the date of BC should be negative (negative x-axis) while the date of AD should be positive (positive x-axis). This would place the origin as the common reference.</span>

3 0
3 years ago
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