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3 years ago

Can someone help me !

Mathematics

1 answer:

rosijanka [135]3 years ago

7 0

Answer:

Step-by-step explanation:

It's the only one with an addition sign...... seems logical, let me know if you got it correct

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Lena has some eggs. She uses 3/5 of the eggs to make waffles and scrambled eggs. She uses 2/3 of the eggs she took to make waffl

grigory [225]

3. 9
--- • 3 = ---
5. 15

2. 10
--- • 5 = ---
3. 15
--------
19/15 or 1 4/15

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3 years ago

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You roll 2 dice. What is the probability of getting two 5's?

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2 years ago

Which expression is equivalent to 8a + 20?

Darina [25.2K]

To determine the expression that is equivalent to 8a + 20, all you have to do is find the common denominator and divide the values by it.

8a + 20
8a/4 + 20/4
4(2a + 5).

The correct solution would cue the second option - 4(2a + 5).

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3 years ago

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a cell phone company plans to market a new smartphone. they have already sold 612 units durning the first week of the campaign.

Vadim26 [7]

The first term is 612.

The common ratio is 1.08 and

The recursive rule is $a_{n} = a^{n-1} \times r$

Step-by-step explanation:

the question to the problem is to write the values of the first term, common ratio, and expression for the recursive rule.

The first term :

In geometric sequence, the first term is given as $a_{1}$ .

⇒ $a_{1} = 612$

Now, the geometric sequence follows as 612, 661, ........

The common ratio (r) :

It is the ratio between two consecutive numbers in the sequence.

Therefore, to determine the common ratio, you just divide the number from the number preceding it in the sequence.

⇒ r = 661 divided by 612

⇒ r = 1.08

To find the recursive rule :

A geometric series is of the form a,ar,ar2,ar3,ar4,ar5........

Here, first term $a_{1} = a$ and other terms are obtained by multiplying by r.

Observe that each term is r times the previous term.
Hence to get nth term we multiply (n−1)th term by r .

The recursive rule is of the form $a_{n} = a^{n-1} \times r$

This is called recursive formula for geometric sequence.

We know that r = 1.08 and $a_{1}$ = 612.

To find the second term $a_{2}$ , use the recursive rule $a_{n} = a^{n-1} \times r$

⇒ $a_{2} = a^{2-1}\times r$

⇒ $a_{2} = a^{1}\times r$

⇒ $a_{2} = 612\times 1.08$

⇒ $a_{2} = 661$

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3 years ago

A teacher passes cards out to students. She has 52 cards. She gives one card to each student at a time to each student until all

Zarrin [17]

The problem presents 2 variables and 2 conditions to follow to determine the approach in solving the problem. The variables are 52 cards, and 9 cards. The 2 conditions presented would be the teacher giving out one card to each student at a time to each student until all of them are gone. The second variable is more likely made as a clue and the important variable that gives away the approach to be used. The approach to be used is division. This is to ensure that there will be students receiving the 9 cards. Thus, we do it as this: 52 / 9 = ?

The answer would be 5.77778 (wherein 7 after the decimal point is infinite and 8 would just be the rounded of number). This would ensure us that there will be 5 students that can receive 9 cards but there will be 7 cards remaining which goes to the last student, which is supposed to be 8 since she gives one card to each student at a time to each student. So the correct answer would be just 4 students. The fifth student will only receive 8 cards and the last student would have 8, too.

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3 years ago

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