All categories

3 years ago

All 3 plz it would help me alot

Mathematics

1 answer:

kow [346]3 years ago

4 0

Answer:

Polygon, concave

Polygon, convex

Not a polygon

You might be interested in

Absolute values can be _____<br><br><one word>

bulgar [2K]

Positive
Yo is this math?

6 0

3 years ago

Robert plays cricket. He hit the ball in such a way that it goes up 180 feet

PilotLPTM [1.2K]

Answer:

4 feet per second

Step-by-step explanation:

Hi there!

$v=D/t$ where v is velocity (speed), D is distance and t is time

Plug in the known values (D=180 feet, t=45 seconds)

$v=180/45\\v=4$

Therefore, the speed of the ball is 4 feet per second.

I hope this helps!

4 0

3 years ago

Read 2 more answers

Two airplanes are flying in the air at the same height. Airplane A is flying east at 300mi/h and airplane B is flying north at 2

Ipatiy [6.2K]

Answer:

$\frac{dAB}{dt}=340 mil/h$

Step-by-step explanation:

The change of distance over time of the plain A is 300 mi/hour and 200 mi/hour for plane B. O is the point of the airport.

So, the distance from A to O AO = 90 miles and BO = 120 miles.

Now, we have a right triangle here. We can use the Pythagorean theorem, so the distance between the planes will be:

$AB^{2} =AO^{2}+BO^{2}$ (1)

$AB =\sqrt{AO^{2}+BO^{2}}=$

$AB =\sqrt{90^{2}+120^{2}}=150 miles$

If we take the derivative of the equation (1) we could find the change of the distance between planes.

$2AB\frac{dAB}{dt}=2AO\frac{dAO}{dt}+2BO\frac{dBO}{dt}$

$2*150\frac{dAB}{dt}=2*90*300+2*120*200=102000 mil/h$

$\frac{dAB}{dt}=\frac{102000}{150*2}$

Finally,

$\frac{dAB}{dt}=340 mil/h$

I hope it helps you!

6 0

3 years ago

How many times can 535 go into 1035

ICE Princess25 [194]

Only once, any number higher will pass it

3 0

3 years ago

There are 70 students in the school band. 40% of them are sixth graders, 20% are seventh graders, and the rest are eighth grader

guajiro [1.7K]

Answer:

Sixth graders: 14

Seventh graders: 28

Eighth graders: 28

Step-by-step explanation:

To solve this you just have to use a rule of three to solve the percentages, remember that the 100% will be the 70 students, and we solve each case separetly:

70 students= 100%

sixth grades= 40%

Sixth grades= (40*70)/100

Sixth graders= 28

70 students= 100%

seventh grades= 20%

seventh graders= (20*70)/100

Seventh graders=14

So if we have that the rest of the students are eighth graders, we just add up the sixth and seventh graders and withdraw them from the total:

28+14=42

70-42=28

SOwe have that the eighth graders are 28

7 0

3 years ago

All 3 plz it would help me alot​

All 3 plz it would help me alot