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Natasha2012 [34]
3 years ago
10

1 28 3 140 fill in the blanks

Mathematics
1 answer:
exis [7]3 years ago
7 0

Answer:

??? what are you asking to fill in

Step-by-step explanation:

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What are the prime factors of 48, in index form
Vikki [24]
Not sure what index form is but
48=2 times 2 times 2 times 2 times 3
this is also
48=2^3 times 3


7 0
3 years ago
Read 2 more answers
4 lines are shown. A line with points T, R, W intersects a line with points S, R, V at point R. Another line extends from point
lianna [129]

Answer:

The Answer is B

Step-by-step explanation:

Edgenuity ;)

4 0
3 years ago
What is the value of the following expression: w^2 + 2 + 48 divided by 2z. If w = 5 and z = 8
velikii [3]

Answer:

Replace w and z with the given values:

5^2 + 2 + 48 / 2(8)

Simplify:

75/16 = 4 and 11/16

Step-by-step explanation:

hopes this helps

-Unknown

4 0
3 years ago
Could someone plz help I need the answers by tonight
Maksim231197 [3]

Answer:

7)  C) PQR ≈ TSR

8) B)  3

9) D) 102 ft

10) D) 21

11) C) 45

Step-by-step explanation:

7) C) PQR ≈ TSR

8) 2 * 6 = 12

so 4x = 12

      x = 3

9)

24/20 = x/85

x = 24 * 85 / 20

x = 202 ft

10)

QT/35 = 24/40

QT/35 = 3/5

QT = 35 * 3 / 5

QT = 21

11)

ΔKLM ≈ΔXYZ

9/4 = 2.25

So

XY = 9 ---> given

YZ = 7 * 2.25 = 15.75

XZ = 9 * 2.25  = 20.25

Perimeter ΔXYZ = 9 + 15.75 + 20.25 = 45

7 0
3 years ago
In a restaurant, the proportion of people who order coffee with their dinner is p. A simple random sample of 144 patrons of the
mote1985 [20]
<h2>Answer with explanation:</h2>

Given : In a restaurant, the proportion of people who order coffee with their dinner is p.

Sample size : n= 144

x= 120

\hat{p}=\dfrac{x}{n}=\dfrac{120}{144}=0.83333333\approx0.8333

The null and the alternative hypotheses if you want to test if p is greater than or equal to 0.85 will be :-

Null hypothesis : H_0: p\geq0.85   [ it takes equality (=, ≤, ≥) ]

Alternative hypothesis : H_1: p  [its exactly opposite of null hypothesis]

∵Alternative hypothesis is left tailed, so the test is a left tailed test.

Test statistic : z=\dfrac{\hat{p}-p}{\sqrt{\dfrac{p(1-p)}{n}}}

z=\dfrac{0.83-0.85}{\sqrt{\dfrac{0.85(1-0.85)}{144}}}\\\\=-0.561232257678\approx-0.56

Using z-vale table ,

Critical value for 0.05 significance ( left-tailed test)=-1.645

Since the calculated value of test statistic is greater than the critical value , so we failed to reject the null hypothesis.

Conclusion : We have enough evidence to support the claim that p is greater than or equal to 0.85.

8 0
3 years ago
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