I believe the answer is Wild
Answer:
8$ left
Step-by-step explanation:
6x2= 12. 20-12= 8. He has 8$ left.
Let A : getting an odd number (i.e. 1,3 or 5), B: getting a number greater than 4 (i.e 5 or 6) . So, the required probability is P(A∪B)=P(A)+P(B)−P(A∩B)=36+26−16=46=23
