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3 years ago

9

I don’t understand these type of questions

1 answer:

storchak [24]3 years ago

6 0

Answer:

5=135

7=45

Step-by-step explanation:

Set them equal to 180. So i started plugging in numbers and subtracting them by 90. Then add it back to the number until i got 180.

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3 ft<br> 10 ft<br> Perimeter:<br> Area:

Crazy boy [7]

Step-by-step explanation:

The area = 3 × 10 = 30

The perimeter = 2(3 + 10) = 26

please give me a brainliest answer

8 0

2 years ago

D<br> Evaluate<br> arcsin<br> (6)]<br> at x = 4.<br> dx

sineoko [7]

Answer:

$\frac{1}{2\sqrt{5} }$

Step-by-step explanation:

Let, $\text{sin}^{-1}(\frac{x}{6})$ = y

sin(y) = $\frac{x}{6}$

$\frac{d}{dx}\text{sin(y)}=\frac{d}{dx}(\frac{x}{6})$

$\frac{d}{dx}\text{sin(y)}=\frac{1}{6}$

$\frac{d}{dx}\text{sin(y)}=\text{cos}(y)\frac{dy}{dx}$ ---------(1)

$\frac{1}{6}=\text{cos}(y)\frac{dy}{dx}$

$\frac{dy}{dx}=\frac{1}{6\text{cos(y)}}$

cos(y) = $\sqrt{1-\text{sin}^{2}(y) }$

= $\sqrt{1-(\frac{x}{6})^2}$

= $\sqrt{1-(\frac{x^2}{36})}$

Therefore, from equation (1),

$\frac{dy}{dx}=\frac{1}{6\sqrt{1-\frac{x^2}{36}}}$

Or $\frac{d}{dx}[\text{sin}^{-1}(\frac{x}{6})]=\frac{1}{6\sqrt{1-\frac{x^2}{36}}}$

At x = 4,

$\frac{d}{dx}[\text{sin}^{-1}(\frac{4}{6})]=\frac{1}{6\sqrt{1-\frac{4^2}{36}}}$

$\frac{d}{dx}[\text{sin}^{-1}(\frac{2}{3})]=\frac{1}{6\sqrt{1-\frac{16}{36}}}$

$=\frac{1}{6\sqrt{\frac{36-16}{36}}}$

$=\frac{1}{6\sqrt{\frac{20}{36} }}$

$=\frac{1}{\sqrt{20}}$

$=\frac{1}{2\sqrt{5}}$

4 0

3 years ago

Which event is most likely to occur?

MrRa [10]

Answer: D

Step-by-step explanation:

If the probability is higher, it has a more likely chance to occur.

7 0

3 years ago

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I'll give brainliest

Soloha48 [4]

Answer

Haven't done this for a bit but I think it's 19

Step-by-step explanation:

2 * 2 * 2 = 8

27 - 8 = 19

6 0

3 years ago

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I need help!! someone please help me!

Shtirlitz [24]

Answer:

B

Step-by-step explanation:

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3 years ago