Look at attachment down below. If can’t see let me know

A drawing is 12 inches wide and 10 inches long. Joe wants to enlarge each side by a scale factor of 0.3. What will be the area o

Andreyy89

Answer:

Area of the dilation = 10.8 square inches

Step-by-step explanation:

Given the original dimension

Length = 12inches

Width = 10inches

If they are dilated by a factor of 0.3

New length = 0.3 * 12 = 3.6in

New width = 0.3 * 10 = 3in

Area of the dilation = 3.6 * 3

Area of the dilation = 10.8 square inches

3 0

3 years ago

A programmer plans to develop a new software system. In planning for the operating system that he will use, he needs to estimat

Vedmedyk [2.9K]

Using the z-distribution, we have that:

a) A sample of 601 is needed.

b) A sample of 93 is needed.

c) A. Yes, using the additional survey information from part (b) dramatically reduces the sample size.

In a sample with a number n of people surveyed with a probability of a success of $\pi$ , and a confidence level of $\alpha$ , we have the following confidence interval of proportions.

$\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}$

In which z is the z-score that has a p-value of $\frac{1+\alpha}{2}$ .

The margin of error is:

$M = z\sqrt{\frac{\pi(1-\pi)}{n}}$

95% confidence level, hence $\alpha = 0.95$ , z is the value of Z that has a p-value of $\frac{1+0.95}{2} = 0.975$ , so $z = 1.96$ .

For this problem, we consider that we want it to be within 4%.

Item a:

The sample size is <u>n for which M = 0.04.</u>

There is no estimate, hence $\pi = 0.5$

$M = z\sqrt{\frac{\pi(1-\pi)}{n}}$

$0.04 = 1.96\sqrt{\frac{0.5(0.5)}{n}}$

$0.04\sqrt{n} = 1.96\sqrt{0.5(0.5)}$

$\sqrt{n} = \frac{1.96\sqrt{0.5(0.5)}}{0.04}$

$(\sqrt{n})^2 = \left(\frac{1.96\sqrt{0.5(0.5)}}{0.04}\right)^2$

$n = 600.25$

Rounding up:

A sample of 601 is needed.

Item b:

The estimate is $\pi = 0.96$ , hence:

$M = z\sqrt{\frac{\pi(1-\pi)}{n}}$

$0.04 = 1.96\sqrt{\frac{0.96(0.04)}{n}}$

$0.04\sqrt{n} = 1.96\sqrt{0.96(0.04)}$

$\sqrt{n} = \frac{1.96\sqrt{0.96(0.04)}}{0.04}$

$(\sqrt{n})^2 = \left(\frac{1.96\sqrt{0.96(0.04)}}{0.04}\right)^2$

$n = 92.2$

Rounding up:

A sample of 93 is needed.

Item c:

The closer the estimate is to $\pi = 0.5$ , the larger the sample size needed, hence, the correct option is A.

For more on the z-distribution, you can check brainly.com/question/25404151

8 0

2 years ago

DA−2qA=B^3<br> Solve for A

a_sh-v [17]

Answer:

$a=\frac{b^{3} }{d-2q}$

Step-by-step explanation:

i think

8 0

3 years ago

What is the volume of the square pyramid with the base edges 24 ft and height

liberstina [14]

Answer:

A

Step-by-step explanation:

The volume of a pyramid is one third the height times the area of the base.

V = ⅓ h A

The base is a square, so the area is the width times length.

V = ⅓ h wl

Problem is, we don't know the height, only the slant length. But we can use this to find the height.

If we cut a cross section down the middle of the pyramid, we get an isosceles triangle. The base of the triangle is 24, and the legs are 37.

If we cut this triangle in half, we get two right triangles. Each right triangle has a base of 12 and a hypotenuse of 37.

Now we can use Pythagorean theorem to find the height of the triangle, which is also the height of the pyramid.

c² = a² + b²

37² = 12² + h²

h = 35

Now we can find the volume. h = 35, w = 24, and l = 24:

V = ⅓ h wl

V = ⅓ (35) (24) (24)

V = 6720

So the volume is 6720 ft³, or answer A.

8 0

3 years ago

What is the quotient of 8/9 and 1 1/3

Art [367]

Hello,

To divide by a fraction, multiply by its reciprocal.

Solution:

8/0 x 3/11

The greatest common factor is 3; cancel 3 out.

The problem will simplify to 8/33.

Faith xoxo

5 0

3 years ago