Answer:
B) 
Step-by-step explanation:
Technically, since the function starts at its maximum, you could say the function is 
, but the answer choices all use sine instead. Therefore, we will have to use the cofunction identity 
and we can see that the correct answer is B.
Answer:
Step-by-step explanation:
sum of angles of a triangle= 180°
x+2x+2x+10=180
5x+10=180
5x=170
x=170/5
x=34
.:
x=34°
2x=34×2=68°
2x+10=2×34+10=68+10=78°
Answer:
11x + 10y - 2w
Step-by-step explanation:
Hello!
To solve for the perimeter, we add up the like terms.
What are like terms?
Like terms are terms with the same variable and degree. 4x and 5y are NOT like terms because the variable is not the same. However, 4x and 3x are like terms, as adding them gives us 7x.
4x and 4x² are not like terms, because the degree of 4x is 1 (degree means the largest exponent), but the degree of 4x² is 2.
Solve for Perimeter:
Combine the like terms by adding them up.
- Perimeter = (8x - 4w) + (3y + 2w) + (3x + 7y)
- P = 8x - 4w + 3y + 2w + 3x + 7y
- P = 8x + 3x + 3y + 7y - 4w + 2w
- P = 11x + 10y - 2w
The perimeter is 11x + 10y - 2w
Given:
The expression is
![\sqrt[3]{48}=\sqrt[3]{8\cdot \_\_}=](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B48%7D%3D%5Csqrt%5B3%5D%7B8%5Ccdot%20%5C_%5C_%7D%3D)
To find:
The simplified form of the expression.
Solution:
We have,
The expression ![\sqrt[3]{48}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B48%7D)
can be written as
![\sqrt[3]{48}=\sqrt[3]{8\cdot 6}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B48%7D%3D%5Csqrt%5B3%5D%7B8%5Ccdot%206%7D)
![\sqrt[3]{48}=\sqrt[3]{8}\cdot \sqrt[3]{6}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B48%7D%3D%5Csqrt%5B3%5D%7B8%7D%5Ccdot%20%5Csqrt%5B3%5D%7B6%7D)
![[\because \sqrt[3]{ab}=\sqrt[3]{a}\sqrt[3]{b}]](https://tex.z-dn.net/?f=%5B%5Cbecause%20%5Csqrt%5B3%5D%7Bab%7D%3D%5Csqrt%5B3%5D%7Ba%7D%5Csqrt%5B3%5D%7Bb%7D%5D)
![\sqrt[3]{48}=2\cdot \sqrt[3]{6}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B48%7D%3D2%5Ccdot%20%5Csqrt%5B3%5D%7B6%7D)
![\sqrt[3]{48}=2\sqrt[3]{6}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B48%7D%3D2%5Csqrt%5B3%5D%7B6%7D)
Therefore, ![\sqrt[3]{48}=\sqrt[3]{8\cdot 6}=2\sqrt[3]{6}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B48%7D%3D%5Csqrt%5B3%5D%7B8%5Ccdot%206%7D%3D2%5Csqrt%5B3%5D%7B6%7D)
.
