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inna [77]
3 years ago
12

Hello Answerers it would be great if you could answer this:

Computers and Technology
2 answers:
meriva3 years ago
5 0

Answer:

A for loop can be used to make something repeat as many times as you program it to, but a while loop only stops when you complete the task, or a certain condition is met. So, if you program a for loop to fill a bucket six times it will fill the bucket six times.

Bess [88]3 years ago
3 0
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What is the purpose of the “little down arrow” next to many different functions in word
Hunter-Best [27]

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A little down arrow is used in word to sort the text and perform different type of function like convert text, Date, Numbers in to ascending or descending order such as A to Z or Z to A. it is used to convert paragraphs, heading, statement convert into ascending or descending.

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What’s good and bad about having social media?
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aliina [53]
If( caryear >= 2000 ):
    print "probably has air bags.\n"
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4 0
3 years ago
An enhancement to a computer accelerates some mode of execution by a factor of 10. The enhanced mode is used 50% of the time, me
Ann [662]

Answer:

The answer is "5.5 and 90.90%"

Explanation:

For point 1:

To calculate the speed from fast mode, its run time without enhancement should be worked out. Designers are aware of which two selves are implicated throughout the accelerated project planning: the empty (50 \%) and the increased stages (50 \%).

Although not enhanced, this would take almost as long (50 \%) and for the combine to give phase; even so, the increased phase would've been 10 times longer, as well as 500 \%. Thus the corresponding total speed without enhancement is =50\% + 500\% = 550\%.

Its overall speed is:

=\frac{\text{Accelerated runtime}}{ \text{accelerated  runtime}} = \frac{550 \%}{ 100 \%}= 5.5

For point 2:

We re-connect these figures in Amdahl's Law throughout order to identify how long it would take for both the initial implementation:

\text{Vectorized fraction}= \frac{\text{Overall velocity}\times \text{Accelerated acceleration}-\text{Accelerated acceleration}}{\text{Overall acceleration} \times \text{Accelerated acceleration}-\text{Overall acceleration}}

                              = \frac{5.5  \times 10 -10 }{ 5.5 \times 10 - 5.5}\\\\=\frac{45}{49.5}\\\\=0.9090\\\\=90.90\%

5 0
3 years ago
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