If you have
|a|=b, then solve for the variable in euations
a=b and a=-b
for ineqalities, it is much trickier
for
|a|>b, assume a>b and a<-b
for
|a|<b, asssume -b<a<b
Good job, you got the equations! XD
I'll just help you solve
Multiply the 2nd row by 9
<span>9x+9y=117</span>
<span><span><span>9x+27y=207
</span></span></span>Subtract the 2nd row from the 1st row
<span><span><span>−18y=−90
</span></span></span>Divide both sides by <span>−18</span>
<span><span><span>y=<span><span>−90/</span><span>−18
</span></span></span></span>Two negatives make a positive
<span><span>y=<span><span>90/</span><span>18</span></span></span><span></span></span><span>
y = 5
Substitute 5 into an equation
9x+9(5)=11<span>7
</span>9x+45=11<span>7
</span>Subtract <span>45</span> from both sides
<span><span><span>9x=117−45
</span></span></span>9x=7<span>2
</span>Divide both sides by <span><span>9</span></span>
x = ___
Hope this will help</span></span>
Answer:
well bcs we cool so appreciated <3 periodTH lolz
Step-by-step explanation:
Solve for x over the real numbers:
x^3 (x^2 - 4) = 0
Split into two equations:
x^3 = 0 or x^2 - 4 = 0
Take cube roots of both sides:
x = 0 or x^2 - 4 = 0
Add 4 to both sides:
x = 0 or x^2 = 4
Take the square root of both sides:
Answer: x = 0 or x = 2 or x = -2
