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scZoUnD [109]
3 years ago
14

Pls HELP me on this I'm not good at it (QS 14)

Mathematics
2 answers:
Katen [24]3 years ago
6 0
You'll have to find the volume of the smaller rectangle and the larger rectangle separately, then add them together. 

For the larger rectangle: V = length x width x height
V = 10 x 6 x 4 = 240 

Now you use the same equation to find the smaller rectangle.
V = lwh
V = 4 x 3 x 6 = 72

Add the two volumes together to get the volume of the entire composite figure. 
240 + 72 = 312
Nutka1998 [239]3 years ago
4 0
The answer is 314

I hope this helps
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valkas [14]
95/100 = 0.95 <== if she missed 5 out of 95, then she got 95 out of 100
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3 years ago
Read 2 more answers
Point A is located at -0.75 and point B is located at 1/4
Murrr4er [49]

Answer:

-0.25

Step-by-step explanation:

need to find the halfway point (average) between -0.75 and 0.25 (same as 1/4)

To get average, add them together: (-0.75) + (0.25) = -0.5, divide by two since there are two numbers, to get average -0.25

8 0
2 years ago
_______________________<br> can someone help me solve this question? Thank you.
Zinaida [17]

Answer:

-60

Step-by-step explanation:

Factor the problem out using FOIL.

The end result is: −60x^{2}−84x+9

The value of coefficent a (the number in front of the x^2) is -60.

8 0
2 years ago
What is the simplified form of the expressions?<br> a. −6a2b−1 <br> b. 5/y−3
Karo-lina-s [1.5K]

Answer:

a.

-6a²/ b

b.

5y³

Step-by-step explanation:

a

-6a²b⁻¹

-6a²/ b

b.

5/ y⁻³

5 / 1/ y³

5 * y³/1

5y³

8 0
3 years ago
Use Cramer’s Rule to solve system of equation.
alisha [4.7K]

\left\{\begin{array}{ccc}5x+2y=4\\3x+4y+2z=6\\7x+3y+4z=29\end{array}\right\\\\A=\left[\begin{array}{ccc}5&2&0\\3&4&2\\7&3&4\end{array}\right]\\\\\det A=5\cdot4\cdot4+3\cdot3\cdot0+2\cdot2\cdot7-7\cdot4\cdot0-3\cdot2\cdot5-3\cdot2\cdot4=54\\W_x=\left[\begin{array}{ccc}4&2&0\\6&4&2\\29&3&4\end{array}\right]\\\det W_x=4\cdot4\cdot4+2\cdot2\cdot29+6\cdot3\cdot0-29\cdot4\cdot0-3\cdot2\cdot4-6\cdot2\cdot4=108

W_y=\left[\begin{array}{ccc}5&4&0\\3&6&2\\7&29&4\end{array}\right]\\\det W_y=5\cdot6\cdot4+3\cdot29\cdot0+4\cdot2\cdot7-7\cdot6\cdot0-29\cdot2\cdot5-3\cdot4\cdot4=-162\\W_z=\left[\begin{array}{ccc}5&2&4\\3&4&6\\7&3&29\end{array}\right]\\\det W_z=5\cdot4\cdot29+3\cdot3\cdot4+6\cdot2\cdot7-7\cdot4\cdot4-3\cdot6\cdot5-3\cdot2\cdot29=324\\\\x=\dfrac{\det W_x}{\det A}=\dfrac{108}{54}=2\\\\y=\dfrac{\det W_y}{\det A}=\dfrac{-62}{54}=-3\\\\z=\dfrac{\det W_z}{\det A}=\dfrac{324}{54}=6

5 0
3 years ago
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