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3 years ago

14

Pls HELP me on this I'm not good at it (QS 14)

2 answers:

Katen [24]3 years ago

6 0

You'll have to find the volume of the smaller rectangle and the larger rectangle separately, then add them together.

For the larger rectangle: V = length x width x height
V = 10 x 6 x 4 = 240

Now you use the same equation to find the smaller rectangle.
V = lwh
V = 4 x 3 x 6 = 72

Add the two volumes together to get the volume of the entire composite figure.
240 + 72 = 312

Nutka1998 [239]3 years ago

4 0

The answer is 314

I hope this helps

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eimsori [14]

Wouldn't all the angles equal 180? We've been trying to learn these but I think so. Subtract both numbers by 180 and it should be the answer. Sorry if it's wrong but I'm not sure. I kinda hope this helps you any

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3 years ago

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Find the total surface area of this cuboid

Harman [31]

Step-by-step explanation:

☄ $\underline{ \underline{ \sf{Given}}}:$

Length ( l ) = 4 cm
Width ( w ) = 2 cm
Height ( h ) = 5 cm

☄ $\underline{ \underline{ \sf{To \: find}}} :$

Total surface area of a cuboid

❅ $\underline{ \underline{ \text{Solution}}}:$

✑ $\boxed{ \text{TSA = 2lw + 2lh + 2hw}}$

Plug the known values :

⟼ $\sf{2 \times 4 \times 2 + 2 \times 4 \times 5 + 2 \times 5 \times 2}$

⟼ $\sf{16 + 40 + 20}$

⟼ $\boxed{\sf{76 \: {cm}}^{2} }$

$\red{ \boxed{ \boxed{ \tt{⟿ \: Our \: final \: answer : 76 \: {cm}}^{2} }}}$

Hope I helped !♡

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4 0

3 years ago

PLEASE HELP WITH THIS!!!<br><br><br>solve for h <br><br><br>6/h+=3

seropon [69]

Your answer is h=2.
Explanation:
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6 0

3 years ago

What are the relative frequencies, to the nearest hundredth, of the rows of the two way table?

Nookie1986 [14]

Answer: A B

Group A 0.25 0.75

Group B 0.45 0.55

Step-by-step explanation:

Since we have given that

Number of people of A in Group A = 15

Number of people of B in Group A = 45

Number of people of A in Group B = 20

Number of people of B in Group B = 25

Total number of people in Group A = 15+45 = 60

Total number of people in Group B = 20+25 = 45

So, Relative frequencies will be given below:

Relative frequency of A in Group A is given by

$\frac{15}{60}=0.25$

Relative frequency of B in Group A is given by

$\frac{45}{60}=0.75$

Relative frequency of A in Group B is given by

$\frac{20}{45}=0.45$

Relative frequency of B in Group B is given by

$\frac{25}{45}=0.55$

Hence, A B

Group A 0.25 0.75

Group B 0.45 0.55

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3 years ago

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lbvjy [14]

Hi,

The answer is false.

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3 years ago

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