8 + 11 = 40
there is a pattern. 1+4=5, the answer from the previous equation 5+2+5=12, 12+3+6=21, 21+8+11=40.
8+11=40
Let First Sphere be the Original Sphere
its Radius be : r
We know that Surface Area of the Sphere is : 4π × (radius)²
⇒ Surface Area of the Original Sphere = 4πr²
Given : The Radius of Original Sphere is Doubled
Let the Sphere whose Radius is Doubled be New Sphere
⇒ Surface of the New Sphere = 4π × (2r)² = 4π × 4 × r²
But we know that : 4πr² is the Surface Area of Original Sphere
⇒ Surface of the New Sphere = 4 × Original Sphere
⇒ If the Radius the Sphere is Doubled, the Surface Area would be enlarged by factor : 4
The answer is B
You would first move 3 coordinates over on the x axis and then 4 coordinates up the y axis.
cot x = cos x / sin x
cot x = .85 / .52 = 1.6346