Answer:
0.08 ft/min
Explanation:
To get the speed at witch the water raising at a given point we need to know the area it needs to fill at that point in the trough (the longitudinal section), which is given by the height at that point.
So we need to get the lenght of the sides for a height of 1 foot. Given the geometry of the trough, one side is the depth <em>d</em> and the other (lets call it <em>l</em>) is given by:
since the difference between the upper and lower base is the increase in the base and we are only at halft the height.
Now we can calculate the longitudinal section <em>A</em> at that point:
And the raising speed <em>v </em>of the water is given by:
where <em>q</em> is the water flow (1 cubic foot per minute).
Answer:
u = 6.667 cm
Explanation:
given,
Focal length of the concave mirror, f = 20 cm
magnification factor = 1.5
we know,
v is the distance of the image
u is the distance of the object
v = -1.5 u
Using mirror formula
u = 6.667 cm
distance of the person from the mirror is equal to 6.667 cm.
Answer:
a) L= 3568 m
b) 9×10^{-5} sec
c) 8.92×10^{-5} sec
Explanation:
runway length on the Earth L_o = 3600 m
Speed of the spacecraft flying past v= 4.00×10^7 m/s
then Einstein's length contraction theory,
Solving we get L= 3568 m
b) Time interval for an observer on earth when the spacecraft is directly over one end of the runway until it is directly over the other end.
L_o= 3600 m
speed v= 4.00×10^7 m/s
Then time interval Δt = L_o/v= = 9×10^{-5} sec
c) for the pilot the time interval will be
Δt_o = L/v = = 8.92×10^{-5} sec
Answer:
<h2>1) There is no work done by the machine because</h2><h2>B) The object has not moved</h2><h2>2) There is no work done by the prisoner because</h2><h2>D) The prisoner does no work because the wall goes no distance</h2><h2>3) The kinetic energy when it is half the way down is</h2><h2>6.0 J</h2>
Explanation:
1) As we know that the work done is the product of force and displacement
It is given as
so if the object is not displaced due to the force exerted by the object then the work done by the object must be ZERO
so correct answer is
B) The object has not moved
2) As we know that the work done is the product of force and displacement
It is given as
As we know that the wall is not displaced due to applied force so here work done by the prisoner must be zero
D) The prisoner does no work because the wall goes no distance
3) As we know by work energy theorem that work done by all forces is equal to change in its kinetic energy
So we will have
so we will have
now when cart moves half the distance then again using the same