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kondor19780726 [428]
2 years ago
6

☆ Correct and rewrite the following statements:

Physics
1 answer:
kvv77 [185]2 years ago
6 0

Answer:

<h3>e)</h3><h3><u>Question</u><u>:</u><u>-</u></h3>
  • Electroplating is based on magnetic effect of electricity.
<h3><u>Answer</u><u>:</u><u>-</u></h3>
  • <em>It's</em><em> </em><em>incorrect</em><em> </em><em>sentence</em><em> </em>
  • As we know that, while electroplating there are two rods, one becoming cathode and another one becoming anode. During electroplating, when electricity is given through the rods, the anode produces positive ions which gets received at the cathode rod and negative ions produced at cathode collects at anode rod which results to the plating of the desired substance. Here, it is a chemical effect of electricity resulting to plating.

<u>So correct sentence is:</u>

  • <em>Electroplating</em><em> </em><em>is</em><em> </em><em>based</em><em> </em><em>of</em><em> </em><em>chemical</em><em> </em><em>effect</em><em> </em><em>of</em><em> </em><em>electricity</em><em>.</em><em> </em>

<h3>f)</h3><h3><u>Question</u><u>:</u><u>-</u></h3>
  • An electric bulb glows due to the chemical effect of electricity.
<h3><u>Answer</u><u>:</u><u>-</u></h3>
  • <em>It's</em><em> </em><em>incorrect</em><em> </em><em>sentence</em><em> </em>
  • As we know that, in an electric bulb there is a filament. When electricity is given in that filament of the electric bulb, the filament gets intensely heated up and results to the emission of light. Due to this heating of the filament due to electricity the electric bulb glows.

<u>So correct sentence is:</u>

  • <em>A</em><em>n electric bulb glows due to the </em><em>h</em><em>e</em><em>a</em><em>t</em><em>i</em><em>n</em><em>g</em><em> </em><em>effect of electricity.</em>
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A 13.5 μF capacitor is connected to a power supply that keeps a constant potential difference of 24.0 V across the plates. A pie
liubo4ka [24]

Answer:

Explanation:

Capacitance of the capacitor = 13.5μF

Voltage across plate is 24V

Dielectric constant k=3.55.

a. Energy in capacitor is given by

E=1/2CV^2

We want to calculate energy without the dielectric substance

Given that C=13.5 μF and V=24V

The capacitance give is with dielectric so we need to remove it

C=kCo

Co=C/k

Then the Co=13.5μF/3.55

Co=3.803μF

Then

E=(1/2)×3.803×10^-6×24^2

E=1.1×10^-3J

E=1.1mJ

b. Energy in capacitor is given by

E=1/2CV^2

The capacitance given is with a dielectric, so we are going to apply it direct.

Given that C=13.5 μF and V=24V

Then

E=(1/2)×13.5×10^-6×24^2

E=3.89×10^-3J

E=3.9mJ

c. The energy without dielectric is 1.1mJ and the energy with dielectric is 3.9mJ

The energy increase when the dielectric material is added

d. Dielectrics in capacitors serve three purposes: to keep the conducting plates from coming in contact, allowing for smaller plate separations and therefore higher capacitances;

Therefore, Since dielectric allow higher capacitance, and energy of a capacitor is directly proportional to the capacitance, then the higher the capacitance the higher the energy.

6 0
3 years ago
Humans cannot convert the Sun's energy into glucose for themselves because humans lack _____.
rosijanka [135]
Human lack chlorophyll, which is the function that collects energy from the Sun to conduct photosynthesis.
3 0
2 years ago
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An elevator and its load have a combined mass of 1650 kg. Find the tension in the supporting cable when the elevator, originally
gizmo_the_mogwai [7]

Answer:

Tension in the supporting cable is = 4,866 N ≅4.9 KN

Explanation:

First of all, we need to understand that tension is a force, so the motion law

F = Ma applies perfectly.

From Newtons third law of motion, action and reaction are equal and opposite. This means that the force experienced by the elevator, is equal to the tension experienced by the spring.

Parameters given:

Mass of load = 1650 kg

Acceleration of load = ?

The acceleration of the load can be obtained by diving the change in velocity by the time taken. But we need to know the time taken for the motion to 41 m.

Time taken = distance covered / velocity

= \frac{41m}{11m/s} = 3.73 seconds

∴Acceleration = ( initial velocity - final velocity )/ time taken

Note: Final velocity is = 0 since the body came to a rest.

Acceleration = \frac{11 - 0 m/s}{3.73s} = 2.95m/s^{2}

Force acting on the cable = mass of elevator × acceleration of elevator

= 1650 × 2.95 = 4869.5 kg ≅ 4.9 KN

6 0
3 years ago
Figure 9.27
liraira [26]
Hcchhchchhhchchchcnjnnnnnn
3 0
3 years ago
A 2.4-m high 200-m2 house is maintained at 22°C by an air-conditioning system whose COP, is 3.2. It is estimated that the kitch
kotegsom [21]

Answer:

The amount that is "vented" out by "the fans" is <u>$0.50</u> for 10 hours.

Option: a

<u>Explanation</u>:

"Energy discharged by air in every hour" can be determined by,

\mathrm{Q}=\mathrm{m}_{\mathrm{air}} \mathrm{C}_{\mathrm{p}} \Delta \mathrm{T}

Q = heat energy (Joules, J)  

m = mass of a substance (kg)  

c = specific heat (units J/kg∙K)  

\mathrm{m}_{\mathrm{air}}=\rho \mathrm{v}

\text { Density of air } \rho=1.20 \mathrm{kg} / \mathrm{m}^{3}

\text { Density of air } \rho=1.20 \times 200 \times 2.4

\text { Density of air } \rho=576 \mathrm{kg}

∆T = 10 hours

\text { Specific Heat Capacities of Air. The nominal values used for air at } 300 \mathrm{K} \text { are } \mathrm{C_P}=1.00 \mathrm{kJ} / \mathrm{kg} . \mathrm{K}

Q = 576 × 1.00 × 10

Q = 5760 kJ/hours

W = 1.6 kwh

We know that, “Coefficient of performance” (COP)

\mathrm{Cop}=\frac{Q}{w}

\mathrm{W}=\frac{Q}{\mathrm{cop}}

Given that, COP = 3.2

\mathrm{W}=\frac{1.6}{3.2}

W = 0.5 kwh

The unit cost of electricity is $0.10/kWh

The unit cost of electricity is $0.10/kWh

Unit electricity cost for 10 hours = 0.5 × 10 × 0.1$

Unit electricity cost for 10 hours = $0.5

The amount that is "vented out" by "the fans" is $0.50 for 10 hours.

6 0
3 years ago
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