If you were to subtract 6 from 15 you would see that Quinn would have 9 gold fish, 9+6= 15
F(5) = 3(5) - 9 = 6
g o f (5) = g(6) = 6^2 = 36 answer
<h3>Given:</h3>
<h3>Note that:</h3>
<h3>
To find:</h3>
The circumference of the circular playing field.
<h3>Solution:</h3>

We'll have to multiply 2, π and radius.
Substitute the values according to the formula.



<u>Therefore</u><u>,</u><u> </u><u>the</u><u> </u><u>circumference</u><u> </u><u>of</u><u> </u><u>the</u><u> </u><u>circular</u><u> </u><u>playing</u><u> </u><u>field</u><u> </u><u>is</u><u> </u><u>47.12</u><u> </u><u>feets</u><u>.</u>
8 miles ? If I am correct
In total it rained 96.6cm that year but on average it rained 100cm that year.
You would multiply 8.05 times the #of momths which is twelve.