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Tju [1.3M]
3 years ago
9

Find n. 35/49 = 5/n n = (Blank)

Mathematics
2 answers:
aalyn [17]3 years ago
8 0
Cross  multiply
49*5=35*n
n= \frac{49*5}{35}=7
Please mark me as brainiest.

Aloiza [94]3 years ago
7 0

Answer: n=7

Step-by-step explanation:

We are given an equation : \dfrac{35}{49}=\dfrac{5}{n}

To find n , we multiply n on both the sides , we get

\dfrac{35}{49}\times n=\dfrac{5}{n}\times n

\Rightarrow\ \dfrac{35n}{49}=5

Now, we multiply 49  on both sides , we get

\dfrac{35n}{49}\times49=5\times49

35n=245

Divide both sides by 35, we get

\dfrac{35n}{35}=\dfrac{245}{35}\\\\\Rightarrow\ n=7

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Step-by-step explanation:

- 3x² - 6x ← factor out - 3x from each term

= - 3x(x + 2)

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Expand the given power by using Pascal’s triangle. (9a - 10b)^6
xxMikexx [17]

Answer:

531441a^6-3542940a^5b+9841500a^4b^2-14580000a^3b^3+12150000a^2b^4-5400000ab^5+1000000b^6

Step-by-step explanation:

                     1                                n=0

                  1      1                            n=1

                 1   2   1                           n=2

                1  3  3  1                          n=3

              1  4  6  4   1                      n=4

             1  5 10 10 5  1                    n=5

           1 6 15 20 15 6 1                   n=6

This is where n is the exponent in

(x+y)^n.

(x+y)^6=1x^6+6x^5y+15x^4y^2+20x^3y^3+15x^2y^4+6xy^5+1y^6

Now we want to expand:

(9a-10b)^6 or we we can rewrite as (9a+(-10b))^6.

Let's replace x with (9a) and y with (-10b) in the expansion:

(x+y)^6=1x^6+6x^5y+15x^4y^2+20x^3y^3+15x^2y^4+6xy^5+1y^6

((9a)+(-10b))^6

=1(9a)^6+6(9a)^5(-10b)+15(9a)^4(-10b)^2+20(9a)^3(-10b)^3+15(9a)^2(-10b)^4+6(9a)(-10b)^5+1(-10b)^6

Let's simplify a bit:

=9^6a^6-60(9)^5a^5b+15(-10)^2(9)^4a^4b^2+20(9)^3(-10)^3a^3b^3+15(9)^2(-10)^4a^2b^4+6(9)(-10)^5ab^5+(-10)^6b^6

=531441a^6-3542940a^5b+9841500a^4b^2-14580000a^3b^3+12150000a^2b^4-5400000ab^5+1000000b^6

8 0
3 years ago
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