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Ronch [10]
3 years ago
11

What is the correct integer for the following: a deposit of $1000?

Mathematics
1 answer:
Sladkaya [172]3 years ago
6 0

Answer: One hundred thousand

 

Step-by-step explanation:

✌️✌️✌️

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What is the approximate value of the square root of 8 rounded to the nearest tenth?
Elanso [62]

Answer:

Step-by-step explanation:

The square root of 8 to the nearest 100th is 2.83

The 3 is less than 5 so it does not alter the 8 at all.

The answer is 2.8

4 0
3 years ago
Patricia annual Salary was 52,000. She earned a 6% raise what is her new salary
dolphi86 [110]

See picture for solution to your problem.

3 0
3 years ago
Read 2 more answers
Evaluate c (y + 7 sin(x)) dx + (z2 + 9 cos(y)) dy + x3 dz where c is the curve r(t) = sin(t), cos(t), sin(2t) , 0 ≤ t ≤ 2π. (hin
saw5 [17]
Treat \mathcal C as the boundary of the region \mathcal S, where \mathcal S is the part of the surface z=2xy bounded by \mathcal C. We write

\displaystyle\int_{\mathcal C}(y+7\sin x)\,\mathrm dx+(z^2+9\cos y)\,\mathrm dy+x^3\,\mathrm dz=\int_{\mathcal C}\mathbf f\cdot\mathrm d\mathbf r

with \mathbf f=(y+7\sin x,z^2+9\cos y,x^3).

By Stoke's theorem, the line integral is equivalent to the surface integral over \mathcal S of the curl of \mathbf f. We have


\nabla\times\mathbf f=(-2z,-3x^2,-1)

so the line integral is equivalent to

\displaystyle\iint_{\mathcal S}\nabla\times\mathbf f\cdot\mathrm d\mathbf S
=\displaystyle\iint_{\mathcal S}\nabla\times\mathbf f\cdot\left(\dfrac{\partial\mathbf s}{\partial u}\times\dfrac{\partial\mathbf s}{\partial v}\right)\,\mathrm du\,\mathrm dv


where \mathbf s(u,v) is a vector-valued function that parameterizes \mathcal S. In this case, we can take

\mathbf s(u,v)=(u\cos v,u\sin v,2u^2\cos v\sin v)=(u\cos v,u\sin v,u^2\sin2v)

with 0\le u\le1 and 0\le v\le2\pi. Then

\mathrm d\mathbf S=\left(\dfrac{\partial\mathbf s}{\partial u}\times\dfrac{\partial\mathbf s}{\partial v}\right)\,\mathrm du\,\mathrm dv=(2u^2\cos v,2u^2\sin v,-u)\,\mathrm du\,\mathrm dv

and the integral becomes

\displaystyle\iint_{\mathcal S}(-2u^2\sin2v,-3u^2\cos^2v,-1)\cdot(2u^2\cos v,2u^2\sin v,-u)\,\mathrm du\,\mathrm dv
=\displaystyle\int_{v=0}^{v=2\pi}\int_{u=0}^{u=1}u-6u^4\sin^3v-4u^4\cos v\sin2v\,\mathrm du\,\mathrm dv=\pi<span />
4 0
3 years ago
Leah claims that these figures are not similar. When she compared the heights, she wrote 27. Then she compared the bases and got
Flauer [41]

Answer:

<h2>Leah is actually wrong, because those rectangles are similar.</h2>

Step-by-step explanation:

Remember that similarity is about having proportional sides and congruent angles. When we have congruent sides, then those rectangles are congruent not similar.

In this case, to find the similarity, Leah should compare bases and heights thorugh division, because the ratio between heights and the ratio between bases must be equal. So, let's divide.

\frac{21}{6}=3.5

\frac{7}{2}=3.5

As you can observe, both ratios are equal.

Therefore, those rectangles are congruent.

4 0
3 years ago
Due in 1 hour, plz help
snow_lady [41]

Answer:

1. 12/1= rate of change

Step-by-step explanation:

1.

1 mile= 30 seconds

(1,30)

6 miles= 1 1/2 minutes

6 miles=90seconds

(6,90)

Formula: y2-y1/x2-x1

90-30/6-1

60/5

12/1= rate of change

hope its right

3 0
2 years ago
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