Rick wants to use multiplication to solve {k} = 7 \div \dfrac13k=7÷ 3 1 k, equals, 7, divided by, start fraction, 1, divided b
y, 3, end fraction. Which multiplication equation can Rick use? Choose 1 answer: Choose 1 answer: (Choice A) A \dfrac13\times{k} =7 3 1 ×k=7start fraction, 1, divided by, 3, end fraction, times, k, equals, 7 (Choice B) B \dfrac13={k}\times7 3 1 =k×7start fraction, 1, divided by, 3, end fraction, equals, k, times, 7 (Choice C) C \dfrac13\times7 = {k} 3 1 ×7=kstart fraction, 1, divided by, 3, end fraction, times, 7, equals, k
