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3 years ago

PLEASE HELP! (or i die tomorrow)

Mathematics

2 answers:

insens350 [35]3 years ago

7 0

Answer:

16. (0 , -6) 17. (0 , 4) 18. (3, -9)

Step-by-step explanation:

lianna [129]3 years ago

5 0

Answer:

A = (0,-6)

B = (0,4)

C = (3,-9)

Step-by-step explanation:

Take the middle number of the x-coordinates.

A- The number in between 0 and 0 is 0

B- The number in between 2 and -2 is 0

C- The number in between -3 and 9 is 3

Take the middle number of the y-coordinates.

A- The number in between 0 and -12 is -6

B- The number in between 9 and -1 is 4

C- The number in between -3 and -15 is -9

You can also use the midpoint formula; M=(x(1) + x(2))/2 , (y(1) + y(2))/2

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What value of k will result in the quadratic having one rational solution if 4x2+kx+4=0?

PtichkaEL [24]

The value of 'k' in the quadratic Equation $4x^{2}+kx+4=0$ having one rational solution is k is 8.

<h3>What is a Quadratic Equation?</h3>

Quadratic equations are the polynomial equations of degree 2 in one variable of the type $f(x) = ax^{2} + bx + c = 0$ where a, b, c, ∈ R and a ≠ 0.
The standard form of a quadratic equation is $ax^{2} + bx + c = 0$ .

Here, the given equation is $4x^{2}+kx+4=0$

By comparing the given equation with the standard form of the quadratic equation we get,

a = 4

b = k

c = 4

The given quadratic is having one rational solution, which means $b^{2} -4ac=0$

Therefore,

$k^{2} -4 \times 4\times4=0\\k^{2} -64=0\\k^{2} =64\\k=\sqrt{64} \\k=8$

Therefore, the value of k is 8.

Learn more about the quadratic equation is brainly.com/question/8649555

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