Answer:
A
Step-by-step explanation:
Replace the point (0,0) in each inequality
A. y - 4 < 3x - 1
B. y - 1 < 3x - 4
C. y + 4 < 3x - 1
D. y + 4 < 3x + 1
A. 0 - 4 < 3(0) - 1
- 4 < - 1
True
B. 0 - 1 < 3(0) - 4
- 1 < - 4
False
C. y + 4 < 3x - 1
0 + 4 < 3(0) - 1
4 < - 1
False
D. y + 4 < 3x + 1
0 + 4 < 3(0) + 1
4 < 1
False
Answer:
You do Thisbe
Step-by-step explanation:
4 cos² x - 3 = 0
4 cos² x = 3
cos² x = 3/4
cos x = ±(√3)/2
Fixing the squared cosine doesn't discriminate among quadrants. There's one in every quadrant
cos x = ± cos(π/6)
Let's do plus first. In general, cos x = cos a has solutions x = ±a + 2πk integer k
cos x = cos(π/6)
x = ±π/6 + 2πk
Minus next.
cos x = -cos(π/6)
cos x = cos(π - π/6)
cos x = cos(5π/6)
x = ±5π/6 + 2πk
We'll write all our solutions as
x = { -5π/6, -π/6, π/6, 5π/6 } + 2πk integer k
Answer: 1/3 x + -1
Step-by-step explanation:
