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Flauer [41]
3 years ago
11

Line I is parallel to line m. If the measure of <6 is 75 , what is the measure of <1 ??

Mathematics
1 answer:
Alexandra [31]3 years ago
7 0

Answer:

∠6=∠2 ( corresponding angles)

∠1+∠2= 180°(Linear Pair)

∠1= 180- 75= 105°

Step-by-step explanation:

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What is the sale price 45% of 69.50
Zolol [24]
   x         55
-------- = ---------
69.50     100

69.50*55= 3822.5
3822.5/100= 38.225
x=$38.22
5 0
3 years ago
When a cylindrical tank is filled with water at a rate of 22 cubic meters per hour, the level of water in the tank rises at a ra
Sergeu [11.5K]

Answer:

r=\sqrt{10}\text{ m}

Step-by-step explanation:

We have been given that when a cylindrical tank is filled with water at a rate of 22 cubic meters per hour, the level of water in the tank rises at a rate of 0.7 meters per hour. We are asked to find the approximate radius of tank in meters.

We will use volume of cylinder formula to solve our given problem as:

V=\pi r^2h, where,

r = Radius,

h = Height of cylinder.

Since the level of water in the tank rises at a rate of 0.7 meters per hour, so height of cylinder would be h = 0.7 meters at V=22\text{ m}^3.

Upon substituting these values in above formula, we will get:

22\text{ m}^3=\frac{22}{7}\cdot r^2(0.7\text{ m})

22\text{ m}^3=\frac{22}{10}\cdot r^2\text{ m}

\frac{10}{22}\cdot\frac{22\text{ m}^3}{\text{m}}=r^2

r^2=\frac{10}{22}\cdot\frac{22\text{ m}^3}{\text{m}}

r^2=10\text{ m}^2

Now, we will take positive square root of both sides as radius cannot be negative.

\sqrt{r^2}=\sqrt{10\text{ m}^2}

r=\sqrt{10}\text{ m}

Therefore, radius of tank would be approximately square root of 10 m.

5 0
3 years ago
HELP FAST!
mote1985 [20]
3(2x + 4) = -6
6x + 12 = -6
6x = -6 - 12
6x = - 18
x = -18/6
x = -3
3 0
3 years ago
Read 2 more answers
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Nat2105 [25]

Answer: 2a^5+5b

Step-by-step explanation:

This is actually pretty simple

The exponent with the same power can be subtracted so

4a^5-2a^5 is 2a^5 like 4x-2x which is equal to 2x

4b+b is equal to 5b

2a^5+5b is your answer

4 0
3 years ago
Iftan A = 39 and sin B = 3 and angles A and B are in Quadrant I, find the value<br> of tan(A + B).
Allushta [10]
The answer is A yupppp
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